提交 36894560 编写于 作者: S stefank

8015422: Large performance hit when the StringTable is walked twice in Parallel Scavenge

Summary: Combine the calls to StringTable::unlink and StringTable::oops_do in Parallel Scavenge.
Reviewed-by: pliden, coleenp
上级 21a11ec2
......@@ -737,7 +737,7 @@ oop StringTable::intern(const char* utf8_string, TRAPS) {
return result;
}
void StringTable::unlink(BoolObjectClosure* is_alive) {
void StringTable::unlink_or_oops_do(BoolObjectClosure* is_alive, OopClosure* f) {
// Readers of the table are unlocked, so we should only be removing
// entries at a safepoint.
assert(SafepointSynchronize::is_at_safepoint(), "must be at safepoint");
......@@ -748,6 +748,9 @@ void StringTable::unlink(BoolObjectClosure* is_alive) {
assert(!entry->is_shared(), "CDS not used for the StringTable");
if (is_alive->do_object_b(entry->literal())) {
if (f != NULL) {
f->do_oop((oop*)entry->literal_addr());
}
p = entry->next_addr();
} else {
*p = entry->next();
......
......@@ -272,7 +272,10 @@ public:
// GC support
// Delete pointers to otherwise-unreachable objects.
static void unlink(BoolObjectClosure* cl);
static void unlink_or_oops_do(BoolObjectClosure* cl, OopClosure* f);
static void unlink(BoolObjectClosure* cl) {
unlink_or_oops_do(cl, NULL);
}
// Invoke "f->do_oop" on the locations of all oops in the table.
static void oops_do(OopClosure* f);
......
......@@ -450,11 +450,9 @@ bool PSScavenge::invoke_no_policy() {
reference_processor()->enqueue_discovered_references(NULL);
}
// Unlink any dead interned Strings
StringTable::unlink(&_is_alive_closure);
// Process the remaining live ones
PSScavengeRootsClosure root_closure(promotion_manager);
StringTable::oops_do(&root_closure);
// Unlink any dead interned Strings and process the remaining live ones.
PSScavengeRootsClosure root_closure(promotion_manager);
StringTable::unlink_or_oops_do(&_is_alive_closure, &root_closure);
// Finally, flush the promotion_manager's labs, and deallocate its stacks.
PSPromotionManager::post_scavenge();
......
Markdown is supported
0% .
You are about to add 0 people to the discussion. Proceed with caution.
先完成此消息的编辑!
想要评论请 注册