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由 Steven Rostedt 提交于
There is lots of places that perform: op = rcu_dereference_raw(ftrace_control_list); while (op != &ftrace_list_end) { Add a helper macro to do this, and also optimize for a single entity. That is, gcc will optimize a loop for either no iterations or more than one iteration. But usually only a single callback is registered to the function tracer, thus the optimized case should be a single pass. to do this we now do: op = rcu_dereference_raw(list); do { [...] } while (likely(op = rcu_dereference_raw((op)->next)) && unlikely((op) != &ftrace_list_end)); An op is always registered (ftrace_list_end when no callbacks is registered), thus when a single callback is registered, the link list looks like: top => callback => ftrace_list_end => NULL. The likely(op = op->next) still must be performed due to the race of removing the callback, where the first op assignment could equal ftrace_list_end. In that case, the op->next would be NULL. But this is unlikely (only happens in a race condition when removing the callback). But it is very likely that the next op would be ftrace_list_end, unless more than one callback has been registered. This tells gcc what the most common case is and makes the fast path with the least amount of branches. Signed-off-by: NSteven Rostedt <rostedt@goodmis.org>
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