Updated documentation comments.

src/Features/CSharp/Portable/QualifyMemberAccess/CSharpQualifyMemberAccessDiagnosticAnalyzer.cs

@@ -16,7 +16,9 @@ protected override string GetLanguageName()
         protected override bool IsAlreadyQualifiedMemberAccess(SyntaxNode node)
             => node.IsKind(SyntaxKind.ThisExpression);
 
-        // If the member is already qualified with `base.`, it cannot be further qualified.
+        // If the member is already qualified with `base.`,
+        // or member is in object initialization context,
+        // or member in property or field initialization, it cannot be qualified.
         protected override bool CanMemberAccessBeQualified(ISymbol containingSymbol, SyntaxNode node)
             => !(node.IsKind(SyntaxKind.BaseExpression) ||
                 node.Parent.Parent.IsKind(SyntaxKind.ObjectInitializerExpression) ||

src/Features/VisualBasic/Portable/Diagnostics/Analyzers/VisualBasicQualifyMemberAccessDiagnosticAnalyzer.vb

@@ -17,7 +17,8 @@ Namespace Microsoft.CodeAnalysis.VisualBasic.QualifyMemberAccess
         End Function
 
         Protected Overrides Function CanMemberAccessBeQualified(containingSymbol As ISymbol, node As SyntaxNode) As Boolean
-            ' If the member is already qualified with `MyBase.`, or `MyClass.`, it cannot be further qualified.
+            ' If the member is already qualified with `MyBase.`, or `MyClass.`,
+            ' or member is in object initialization context, it cannot be qualified.
             Return Not (node.IsKind(SyntaxKind.MyBaseExpression) OrElse node.IsKind(SyntaxKind.MyClassExpression) OrElse node.IsKind(SyntaxKind.ObjectCreationExpression))
         End Function
     End Class