提交 6f7faa0b 编写于 作者: A Alex Crichton

rollup merge of #19736: steveklabnik/gh19662

Fixes #19662.
......@@ -230,8 +230,9 @@ fn add_one(num: &int) -> int {
```
Rust has a feature called 'lifetime elision,' which allows you to not write
lifetime annotations in certain circumstances. This is one of them. Without
eliding the lifetimes, `add_one` looks like this:
lifetime annotations in certain circumstances. This is one of them. We will
cover the others later. Without eliding the lifetimes, `add_one` looks like
this:
```rust
fn add_one<'a>(num: &'a int) -> int {
......@@ -449,6 +450,80 @@ This is the simplest kind of multiple ownership possible. For example, there's
also `Arc<T>`, which uses more expensive atomic instructions to be the
thread-safe counterpart of `Rc<T>`.
## Lifetime Elision
Earlier, we mentioned 'lifetime elision,' a feature of Rust which allows you to
not write lifetime annotations in certain circumstances. All references have a
lifetime, and so if you elide a lifetime (like `&T` instead of `&'a T`), Rust
will do three things to determine what those lifetimes should be.
When talking about lifetime elision, we use the term 'input lifetime' and
'output lifetime'. An 'input liftime' is a lifetime associated with a parameter
of a function, and an 'output lifetime' is a lifetime associated with the return
value of a function. For example, this function has an input lifetime:
```{rust,ignore}
fn foo<'a>(bar: &'a str)
```
This one has an output lifetime:
```{rust,ignore}
fn foo<'a>() -> &'a str
```
This one has a lifetime in both positions:
```{rust,ignore}
fn foo<'a>(bar: &'a str) -> &'a str
```
Here are the three rules:
* Each elided lifetime in a function's arguments becomes a distinct lifetime
parameter.
* If there is exactly one input lifetime, elided or not, that lifetime is
assigned to all elided lifetimes in the return values of that function..
* If there are multiple input lifetimes, but one of them is `&self` or `&mut
self`, the lifetime of `self` is assigned to all elided output lifetimes.
Otherwise, it is an error to elide an output lifetime.
### Examples
Here are some examples of functions with elided lifetimes, and the version of
what the elided lifetimes are expand to:
```{rust,ignore}
fn print(s: &str); // elided
fn print<'a>(s: &'a str); // expanded
fn debug(lvl: uint, s: &str); // elided
fn debug<'a>(lvl: uint, s: &'a str); // expanded
// In the preceeding example, `lvl` doesn't need a lifetime because it's not a
// reference (`&`). Only things relating to references (such as a `struct`
// which contains a reference) need lifetimes.
fn substr(s: &str, until: uint) -> &str; // elided
fn substr<'a>(s: &'a str, until: uint) -> &'a str; // expanded
fn get_str() -> &str; // ILLEGAL, no inputs
fn frob(s: &str, t: &str) -> &str; // ILLEGAL, two inputs
fn get_mut(&mut self) -> &mut T; // elided
fn get_mut<'a>(&'a mut self) -> &'a mut T; // expanded
fn args<T:ToCStr>(&mut self, args: &[T]) -> &mut Command // elided
fn args<'a, 'b, T:ToCStr>(&'a mut self, args: &'b [T]) -> &'a mut Command // expanded
fn new(buf: &mut [u8]) -> BufWriter; // elided
fn new<'a>(buf: &'a mut [u8]) -> BufWriter<'a> // expanded
```
# Related Resources
Coming Soon.
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