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642e34db
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体验新版 GitCode,发现更多精彩内容 >>
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642e34db
编写于
12月 05, 2022
作者:
GreyZeng
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191 addition
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193 deletion
+191
-193
src/main/java/leetcode/medium/LeetCode_0102_BinaryTreeLevelOrderTraversal.java
...e/medium/LeetCode_0102_BinaryTreeLevelOrderTraversal.java
+142
-144
src/main/java/leetcode/medium/LeetCode_0107_BinaryTreeLevelOrderTraversalII.java
...medium/LeetCode_0107_BinaryTreeLevelOrderTraversalII.java
+49
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src/main/java/leetcode/medium/LeetCode_0102_BinaryTreeLevelOrderTraversal.java
浏览文件 @
642e34db
...
...
@@ -7,165 +7,163 @@ import java.util.List;
import
java.util.Map
;
import
java.util.Queue
;
//树的按层遍历
//1. hash表+LinkedList
//2. 仅用LinkedList
//3. 自定义队列
// 笔记:https://www.cnblogs.com/greyzeng/p/16356829.html
// 树的按层遍历
// 1. hash表+LinkedList
// 2. 仅用LinkedList
// 3. 自定义队列
// https://leetcode-cn.com/problems/binary-tree-level-order-traversal/
public
class
LeetCode_0102_BinaryTreeLevelOrderTraversal
{
// 哈希表结合Java自带的LinkedList
public
static
List
<
List
<
Integer
>>
levelOrder3
(
TreeNode
head
)
{
if
(
head
==
null
)
{
return
new
ArrayList
<>();
}
List
<
List
<
Integer
>>
ans
=
new
ArrayList
<>();
// 记录某个节点在第几层
Map
<
TreeNode
,
Integer
>
map
=
new
HashMap
<>();
Queue
<
TreeNode
>
queue
=
new
LinkedList
<>();
// 当前是第几层
int
curLevel
=
0
;
TreeNode
cur
=
head
;
queue
.
offer
(
cur
);
map
.
put
(
cur
,
curLevel
);
List
<
Integer
>
levelRecords
=
new
ArrayList
<>();
while
(!
queue
.
isEmpty
())
{
TreeNode
c
=
queue
.
poll
();
int
level
=
map
.
get
(
c
);
if
(
c
.
left
!=
null
)
{
queue
.
offer
(
c
.
left
);
map
.
put
(
c
.
left
,
level
+
1
);
}
if
(
c
.
right
!=
null
)
{
queue
.
offer
(
c
.
right
);
map
.
put
(
c
.
right
,
level
+
1
);
}
if
(
curLevel
==
level
)
{
levelRecords
.
add
(
c
.
val
);
}
else
{
ans
.
add
(
levelRecords
);
levelRecords
=
new
ArrayList
<>();
levelRecords
.
add
(
c
.
val
);
curLevel
=
level
;
}
}
// 记得要存最后一层的数据
// 哈希表结合Java自带的LinkedList
public
static
List
<
List
<
Integer
>>
levelOrder3
(
TreeNode
head
)
{
if
(
head
==
null
)
{
return
new
ArrayList
<>();
}
List
<
List
<
Integer
>>
ans
=
new
ArrayList
<>();
// 记录某个节点在第几层
Map
<
TreeNode
,
Integer
>
map
=
new
HashMap
<>();
Queue
<
TreeNode
>
queue
=
new
LinkedList
<>();
// 当前是第几层
int
curLevel
=
0
;
TreeNode
cur
=
head
;
queue
.
offer
(
cur
);
map
.
put
(
cur
,
curLevel
);
List
<
Integer
>
levelRecords
=
new
ArrayList
<>();
while
(!
queue
.
isEmpty
())
{
TreeNode
c
=
queue
.
poll
();
int
level
=
map
.
get
(
c
);
if
(
c
.
left
!=
null
)
{
queue
.
offer
(
c
.
left
);
map
.
put
(
c
.
left
,
level
+
1
);
}
if
(
c
.
right
!=
null
)
{
queue
.
offer
(
c
.
right
);
map
.
put
(
c
.
right
,
level
+
1
);
}
if
(
curLevel
==
level
)
{
levelRecords
.
add
(
c
.
val
);
}
else
{
ans
.
add
(
levelRecords
);
return
ans
;
levelRecords
=
new
ArrayList
<>();
levelRecords
.
add
(
c
.
val
);
curLevel
=
level
;
}
}
// 用LinkedList
public
static
List
<
List
<
Integer
>>
levelOrder2
(
TreeNode
head
)
{
if
(
head
==
null
)
{
return
new
ArrayList
<>();
}
List
<
List
<
Integer
>>
ans
=
new
ArrayList
<>();
List
<
Integer
>
levelRecords
=
new
ArrayList
<>();
Queue
<
TreeNode
>
queue
=
new
LinkedList
<>();
TreeNode
curEnd
=
head
;
TreeNode
nextEnd
=
null
;
queue
.
offer
(
curEnd
);
while
(!
queue
.
isEmpty
())
{
TreeNode
c
=
queue
.
poll
();
levelRecords
.
add
(
c
.
val
);
if
(
c
.
left
!=
null
)
{
queue
.
offer
(
c
.
left
);
nextEnd
=
c
.
left
;
}
if
(
c
.
right
!=
null
)
{
queue
.
offer
(
c
.
right
);
nextEnd
=
c
.
right
;
}
if
(
c
==
curEnd
)
{
// 来到新的一层了
curEnd
=
nextEnd
;
ans
.
add
(
levelRecords
);
levelRecords
=
new
ArrayList
<>();
}
}
return
ans
;
// 记得要存最后一层的数据
ans
.
add
(
levelRecords
);
return
ans
;
}
// 用LinkedList
public
static
List
<
List
<
Integer
>>
levelOrder2
(
TreeNode
root
)
{
if
(
null
==
root
)
{
return
new
ArrayList
<>();
}
public
static
class
MyNode
{
public
TreeNode
data
;
public
MyNode
next
;
public
MyNode
(
TreeNode
node
)
{
data
=
node
;
}
List
<
List
<
Integer
>>
result
=
new
ArrayList
<>();
List
<
Integer
>
levelRecords
=
new
ArrayList
<>();
TreeNode
curEnd
=
root
;
TreeNode
nextEnd
=
null
;
Queue
<
TreeNode
>
queue
=
new
LinkedList
<>();
queue
.
offer
(
root
);
while
(!
queue
.
isEmpty
())
{
TreeNode
poll
=
queue
.
poll
();
levelRecords
.
add
(
poll
.
val
);
if
(
null
!=
poll
.
left
)
{
queue
.
offer
(
poll
.
left
);
nextEnd
=
poll
.
left
;
}
if
(
null
!=
poll
.
right
)
{
queue
.
offer
(
poll
.
right
);
nextEnd
=
poll
.
right
;
}
if
(
poll
==
curEnd
)
{
curEnd
=
nextEnd
;
result
.
add
(
levelRecords
);
levelRecords
=
new
ArrayList
<>();
}
}
return
result
;
}
public
static
class
MyQueue
{
public
MyNode
front
;
public
MyNode
end
;
public
int
size
;
public
static
class
MyNode
{
public
TreeNode
data
;
public
MyNode
next
;
public
MyQueue
(
)
{
front
=
null
;
end
=
null
;
}
public
MyNode
(
TreeNode
node
)
{
data
=
node
;
}
}
public
void
offer
(
MyNode
c
)
{
size
++;
if
(
front
==
null
)
{
front
=
c
;
}
else
{
end
.
next
=
c
;
}
end
=
c
;
}
public
static
class
MyQueue
{
public
MyNode
front
;
public
MyNode
end
;
public
int
size
;
public
boolean
isEmpty
()
{
return
size
==
0
;
}
public
MyQueue
()
{
front
=
null
;
end
=
null
;
}
public
MyNode
poll
()
{
size
--;
MyNode
ans
=
front
;
front
=
front
.
next
;
ans
.
next
=
null
;
return
ans
;
}
public
void
offer
(
MyNode
c
)
{
size
++;
if
(
front
==
null
)
{
front
=
c
;
}
else
{
end
.
next
=
c
;
}
end
=
c
;
}
public
boolean
isEmpty
()
{
return
size
==
0
;
}
// 用自定义Queue
public
static
List
<
List
<
Integer
>>
levelOrder
(
TreeNode
root
)
{
List
<
List
<
Integer
>>
ans
=
new
ArrayList
<>();
if
(
root
==
null
)
{
return
ans
;
}
MyNode
head
=
new
MyNode
(
root
);
MyQueue
queue
=
new
MyQueue
();
queue
.
offer
(
head
);
MyNode
curEnd
=
head
;
MyNode
nextEnd
=
null
;
List
<
Integer
>
item
=
new
ArrayList
<>();
MyNode
t
;
while
(!
queue
.
isEmpty
())
{
MyNode
c
=
queue
.
poll
();
if
(
c
.
data
.
left
!=
null
)
{
t
=
new
MyNode
(
c
.
data
.
left
);
queue
.
offer
(
t
);
nextEnd
=
t
;
}
if
(
c
.
data
.
right
!=
null
)
{
t
=
new
MyNode
(
c
.
data
.
right
);
queue
.
offer
(
t
);
nextEnd
=
t
;
}
item
.
add
(
c
.
data
.
val
);
if
(
curEnd
.
data
==
c
.
data
)
{
ans
.
add
(
item
);
item
=
new
ArrayList
<>();
curEnd
=
nextEnd
;
}
}
return
ans
;
public
MyNode
poll
()
{
size
--;
MyNode
ans
=
front
;
front
=
front
.
next
;
ans
.
next
=
null
;
return
ans
;
}
}
public
static
class
TreeNode
{
int
val
;
TreeNode
left
;
TreeNode
right
;
// 用自定义Queue
public
static
List
<
List
<
Integer
>>
levelOrder
(
TreeNode
root
)
{
List
<
List
<
Integer
>>
ans
=
new
ArrayList
<>();
if
(
root
==
null
)
{
return
ans
;
}
MyNode
head
=
new
MyNode
(
root
);
MyQueue
queue
=
new
MyQueue
();
queue
.
offer
(
head
);
MyNode
curEnd
=
head
;
MyNode
nextEnd
=
null
;
List
<
Integer
>
item
=
new
ArrayList
<>();
MyNode
t
;
while
(!
queue
.
isEmpty
())
{
MyNode
c
=
queue
.
poll
();
if
(
c
.
data
.
left
!=
null
)
{
t
=
new
MyNode
(
c
.
data
.
left
);
queue
.
offer
(
t
);
nextEnd
=
t
;
}
if
(
c
.
data
.
right
!=
null
)
{
t
=
new
MyNode
(
c
.
data
.
right
);
queue
.
offer
(
t
);
nextEnd
=
t
;
}
item
.
add
(
c
.
data
.
val
);
if
(
curEnd
.
data
==
c
.
data
)
{
ans
.
add
(
item
);
item
=
new
ArrayList
<>();
curEnd
=
nextEnd
;
}
}
return
ans
;
}
public
static
class
TreeNode
{
int
val
;
TreeNode
left
;
TreeNode
right
;
}
}
src/main/java/leetcode/medium/LeetCode_0107_BinaryTreeLevelOrderTraversalII.java
浏览文件 @
642e34db
//Given a binary tree, return the bottom-up level order traversal of its nodes' values. (ie, from left to right, level by level from leaf to root).
// Given a binary tree, return the bottom-up level order traversal of its nodes' values. (ie, from
// left to right, level by level from leaf to root).
//
//For example:
//Given binary tree [3,9,20,null,null,15,7],
//
For example:
//
Given binary tree [3,9,20,null,null,15,7],
// 3
// / \
// 9 20
// / \
// 15 7
//return its bottom-up level order traversal as:
//[
//
return its bottom-up level order traversal as:
//
[
// [15,7],
// [9,20],
// [3]
//]
//
]
package
leetcode.medium
;
import
java.util.ArrayDeque
;
import
java.util.ArrayList
;
import
java.util.Deque
;
import
java.util.LinkedList
;
import
java.util.List
;
import
java.util.Queue
;
import
java.util.Queue
;
// 笔记:https://www.cnblogs.com/greyzeng/p/16356829.html
// 按层遍历进阶
public
class
LeetCode_0107_BinaryTreeLevelOrderTraversalII
{
public
static
class
TreeNode
{
int
val
;
TreeNode
left
;
TreeNode
right
;
}
public
static
class
TreeNode
{
int
val
;
TreeNode
left
;
TreeNode
right
;
}
public
List
<
List
<
Integer
>>
levelOrderBottom
(
TreeNode
root
)
{
List
<
List
<
Integer
>>
ans
=
new
ArrayList
<>();
Deque
<
List
<
Integer
>>
stack
=
new
ArrayDeque
<>();
if
(
root
==
null
)
{
return
ans
;
}
TreeNode
cur
=
root
;
TreeNode
curEnd
=
cur
;
TreeNode
nextEnd
=
null
;
Queue
<
TreeNode
>
queue
=
new
LinkedList
<>();
queue
.
offer
(
cur
);
List
<
Integer
>
item
=
new
ArrayList
<>();
while
(!
queue
.
isEmpty
()
)
{
cur
=
queue
.
poll
();
if
(
cur
.
left
!=
null
)
{
queue
.
offer
(
cur
.
left
);
nextEnd
=
cur
.
left
;
}
if
(
cur
.
right
!=
null
)
{
queue
.
offer
(
cur
.
right
);
nextEnd
=
cur
.
right
;
}
item
.
add
(
cur
.
val
);
if
(
cur
==
curEnd
)
{
stack
.
push
(
item
);
item
=
new
ArrayList
<>();
curEnd
=
nextEnd
;
}
}
while
(!
stack
.
isEmpty
()
)
{
ans
.
add
(
stack
.
pop
());
}
return
ans
;
}
public
List
<
List
<
Integer
>>
levelOrderBottom
(
TreeNode
root
)
{
if
(
null
==
root
)
{
return
new
ArrayList
<>();
}
Deque
<
List
<
Integer
>>
stack
=
new
ArrayDeque
<>();
List
<
List
<
Integer
>>
result
=
new
ArrayList
<>();
List
<
Integer
>
levelRecords
=
new
ArrayList
<>();
TreeNode
curEnd
=
root
;
TreeNode
nextEnd
=
null
;
Queue
<
TreeNode
>
queue
=
new
LinkedList
<>();
queue
.
offer
(
root
);
while
(!
queue
.
isEmpty
())
{
TreeNode
poll
=
queue
.
poll
();
levelRecords
.
add
(
poll
.
val
);
if
(
null
!=
poll
.
left
)
{
queue
.
offer
(
poll
.
left
);
nextEnd
=
poll
.
left
;
}
if
(
null
!=
poll
.
right
)
{
queue
.
offer
(
poll
.
right
);
nextEnd
=
poll
.
right
;
}
if
(
poll
==
curEnd
)
{
curEnd
=
nextEnd
;
stack
.
push
(
levelRecords
);
levelRecords
=
new
ArrayList
<>();
}
}
while
(!
stack
.
isEmpty
())
{
result
.
add
(
stack
.
poll
());
}
return
result
;
}
}
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