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algorithm
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642e34db
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algorithm
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体验新版 GitCode,发现更多精彩内容 >>
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642e34db
编写于
12月 05, 2022
作者:
GreyZeng
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update notes
上级
efe25c45
变更
2
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Showing
2 changed file
with
191 addition
and
193 deletion
+191
-193
src/main/java/leetcode/medium/LeetCode_0102_BinaryTreeLevelOrderTraversal.java
...e/medium/LeetCode_0102_BinaryTreeLevelOrderTraversal.java
+142
-144
src/main/java/leetcode/medium/LeetCode_0107_BinaryTreeLevelOrderTraversalII.java
...medium/LeetCode_0107_BinaryTreeLevelOrderTraversalII.java
+49
-49
未找到文件。
src/main/java/leetcode/medium/LeetCode_0102_BinaryTreeLevelOrderTraversal.java
浏览文件 @
642e34db
...
...
@@ -7,10 +7,11 @@ import java.util.List;
import
java.util.Map
;
import
java.util.Queue
;
//树的按层遍历
//1. hash表+LinkedList
//2. 仅用LinkedList
//3. 自定义队列
// 笔记:https://www.cnblogs.com/greyzeng/p/16356829.html
// 树的按层遍历
// 1. hash表+LinkedList
// 2. 仅用LinkedList
// 3. 自定义队列
// https://leetcode-cn.com/problems/binary-tree-level-order-traversal/
public
class
LeetCode_0102_BinaryTreeLevelOrderTraversal
{
// 哈希表结合Java自带的LinkedList
...
...
@@ -52,37 +53,35 @@ public class LeetCode_0102_BinaryTreeLevelOrderTraversal {
ans
.
add
(
levelRecords
);
return
ans
;
}
// 用LinkedList
public
static
List
<
List
<
Integer
>>
levelOrder2
(
TreeNode
head
)
{
if
(
head
==
null
)
{
public
static
List
<
List
<
Integer
>>
levelOrder2
(
TreeNode
root
)
{
if
(
null
==
root
)
{
return
new
ArrayList
<>();
}
List
<
List
<
Integer
>>
ans
=
new
ArrayList
<>();
List
<
List
<
Integer
>>
result
=
new
ArrayList
<>();
List
<
Integer
>
levelRecords
=
new
ArrayList
<>();
Queue
<
TreeNode
>
queue
=
new
LinkedList
<>();
TreeNode
curEnd
=
head
;
TreeNode
curEnd
=
root
;
TreeNode
nextEnd
=
null
;
queue
.
offer
(
curEnd
);
Queue
<
TreeNode
>
queue
=
new
LinkedList
<>();
queue
.
offer
(
root
);
while
(!
queue
.
isEmpty
())
{
TreeNode
c
=
queue
.
poll
();
levelRecords
.
add
(
c
.
val
);
if
(
c
.
left
!=
null
)
{
queue
.
offer
(
c
.
left
);
nextEnd
=
c
.
left
;
TreeNode
poll
=
queue
.
poll
();
levelRecords
.
add
(
poll
.
val
);
if
(
null
!=
poll
.
left
)
{
queue
.
offer
(
poll
.
left
);
nextEnd
=
poll
.
left
;
}
if
(
c
.
right
!=
null
)
{
queue
.
offer
(
c
.
right
);
nextEnd
=
c
.
right
;
if
(
null
!=
poll
.
right
)
{
queue
.
offer
(
poll
.
right
);
nextEnd
=
poll
.
right
;
}
if
(
c
==
curEnd
)
{
// 来到新的一层了
if
(
poll
==
curEnd
)
{
curEnd
=
nextEnd
;
ans
.
add
(
levelRecords
);
result
.
add
(
levelRecords
);
levelRecords
=
new
ArrayList
<>();
}
}
return
ans
;
return
result
;
}
public
static
class
MyNode
{
...
...
@@ -125,7 +124,6 @@ public class LeetCode_0102_BinaryTreeLevelOrderTraversal {
ans
.
next
=
null
;
return
ans
;
}
}
// 用自定义Queue
...
...
src/main/java/leetcode/medium/LeetCode_0107_BinaryTreeLevelOrderTraversalII.java
浏览文件 @
642e34db
//Given a binary tree, return the bottom-up level order traversal of its nodes' values. (ie, from left to right, level by level from leaf to root).
// Given a binary tree, return the bottom-up level order traversal of its nodes' values. (ie, from
// left to right, level by level from leaf to root).
//
//For example:
//Given binary tree [3,9,20,null,null,15,7],
//
For example:
//
Given binary tree [3,9,20,null,null,15,7],
// 3
// / \
// 9 20
// / \
// 15 7
//return its bottom-up level order traversal as:
//[
//
return its bottom-up level order traversal as:
//
[
// [15,7],
// [9,20],
// [3]
//]
//
]
package
leetcode.medium
;
import
java.util.ArrayDeque
;
...
...
@@ -22,7 +23,8 @@ import java.util.LinkedList;
import
java.util.List
;
import
java.util.Queue
;
// 笔记:https://www.cnblogs.com/greyzeng/p/16356829.html
// 按层遍历进阶
public
class
LeetCode_0107_BinaryTreeLevelOrderTraversalII
{
public
static
class
TreeNode
{
...
...
@@ -32,38 +34,36 @@ public class LeetCode_0107_BinaryTreeLevelOrderTraversalII {
}
public
List
<
List
<
Integer
>>
levelOrderBottom
(
TreeNode
root
)
{
List
<
List
<
Integer
>>
ans
=
new
ArrayList
<>();
Deque
<
List
<
Integer
>>
stack
=
new
ArrayDeque
<>();
if
(
root
==
null
)
{
return
ans
;
if
(
null
==
root
)
{
return
new
ArrayList
<>();
}
TreeNode
cur
=
root
;
TreeNode
curEnd
=
cur
;
Deque
<
List
<
Integer
>>
stack
=
new
ArrayDeque
<>();
List
<
List
<
Integer
>>
result
=
new
ArrayList
<>();
List
<
Integer
>
levelRecords
=
new
ArrayList
<>();
TreeNode
curEnd
=
root
;
TreeNode
nextEnd
=
null
;
Queue
<
TreeNode
>
queue
=
new
LinkedList
<>();
queue
.
offer
(
cur
);
List
<
Integer
>
item
=
new
ArrayList
<>();
while
(!
queue
.
isEmpty
()
)
{
cur
=
queue
.
poll
(
);
if
(
cur
.
left
!=
null
)
{
queue
.
offer
(
cur
.
left
);
nextEnd
=
cur
.
left
;
queue
.
offer
(
root
);
while
(!
queue
.
isEmpty
())
{
TreeNode
poll
=
queue
.
poll
();
levelRecords
.
add
(
poll
.
val
);
if
(
null
!=
poll
.
left
)
{
queue
.
offer
(
poll
.
left
);
nextEnd
=
poll
.
left
;
}
if
(
cur
.
right
!=
null
)
{
queue
.
offer
(
cur
.
right
);
nextEnd
=
cur
.
right
;
if
(
null
!=
poll
.
right
)
{
queue
.
offer
(
poll
.
right
);
nextEnd
=
poll
.
right
;
}
item
.
add
(
cur
.
val
);
if
(
cur
==
curEnd
)
{
stack
.
push
(
item
);
item
=
new
ArrayList
<>();
if
(
poll
==
curEnd
)
{
curEnd
=
nextEnd
;
stack
.
push
(
levelRecords
);
levelRecords
=
new
ArrayList
<>();
}
}
while
(!
stack
.
isEmpty
()
)
{
ans
.
add
(
stack
.
pop
());
while
(!
stack
.
isEmpty
()
)
{
result
.
add
(
stack
.
poll
());
}
return
ans
;
return
result
;
}
}
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