fixed right join

data/2.MySQL中阶/6.连接查询/3. RIGHT JOIN/right_join.md

@@ -33,9 +33,9 @@ create table employee(
 ## 答案
 
 ```sql
-select e.id, e.name, e.dept
+select e.id, e.name, e.dept_id, d.name
 from department as d
-    right join employee as e on d.id = e.dept
+    right join employee as e on d.id = e.dept_id
 where d.id is null;
 ```
 
@@ -44,27 +44,27 @@ where d.id is null;
 ### A
 
 ```sql
-select e.id, e.name, e.dept
+select e.id, e.name, e.dept_id, d.name
 from employee as e
-    right join department as d on d.id = e.dept
+    right join department as d on d.id = e.dept_id
 where e.id is null;
 ```
 
 ### B
 
 ```sql
-select e.id, e.name, e.dept
+select e.id, e.name, e.dept_id, d.name
 from employee as e
-     right join department as d on d.id = e.dept
+     right join department as d on d.id = e.dept_id
 where d.id is null;
 ```
 
 ### C
 
 ```sql
-select e.id, e.name, e.dept
+select e.id, e.name, e.dept_id, d.name
 from department as d
-    join employee as e on d.id = e.dept
+    join employee as e on d.id = e.dept_id
 where d.id is null;
 ```
 
@@ -72,8 +72,8 @@ where d.id is null;
 ### D
 
 ```sql
-select e.id, e.name, e.dept
+select e.id, e.name, e.dept_id, d.name
 from department as d
-    right join employee as e on d.id = e.dept
+    right join employee as e on d.id = e.dept_id
 where d.id is null;
 ```
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