solution.md

# 成绩统计

**问题描述**

编写一个程序，建立了一条单向链表，每个结点包含姓名、学号、英语成绩、数学成绩和C++成绩，并通过链表操作平均最高的学生和平均分最低的学生并且输出。  
**输入格式**

输入n+1行，第一行输入一个正整数n，表示学生数量；接下来的n行每行输入5个数据，分别表示姓名、学号、英语成绩、数学成绩和C++成绩。注意成绩有可能会有小数。  
**输出格式**

输出两行，第一行输出平均成绩最高的学生姓名。第二行输出平均成绩最低的学生姓名。  

**样例输入**

```
2
yx1 1 45 67 87
yx2 2 88 90 99
```

**样例输出**

```
yx2
yx1
```

请从以下四个选项中选择空白处的内容。

```cpp
#include <bits/stdc++.h>
using namespace std;

int main()
{
    struct student
    {
        string xm;
        int xh;
        double yy;
        double sx;
        double cpp;
    };
    student a[1000];
    int n;
    double sum = 0, min = 301, max = 0;
    string mins, maxs;
    cin >> n;
    for (int i = 0; i < n; i++)
    {
        cin >> a[i].xm >> a[i].xh >> a[i].yy >> a[i].sx >> a[i].cpp;
        sum = a[i].yy + a[i].sx + a[i].cpp;
        __________________
    }
    cout << maxs << endl
         << mins;
    return 0;
}
```



## aop

### before

```cpp

```

### after

```cpp

```

## 答案

```cpp
        if (min > sum)
        {
            min = sum;
            mins = a[i].xm;
        }
        if (max < sum)
        {
            max = sum;
            maxs = a[i].xm;
        }
```
## 选项


### A

```cpp
        if (min < sum)
        {
            min = sum;
            mins = a[i].xm;
        }
        if (max > sum)
        {
            max = sum;
            maxs = a[i].xm;
        }
```

### B

```cpp
        if (min > sum)
        {
            max = sum;
            mins = a[i].xm;
        }
        if (max < sum)
        {
            min = sum;
            maxs = a[i].xm;
        }
```

### C

```cpp
        if (min > sum)
        {
            min = sum;
            maxs = a[i].xm;
        }
        if (max < sum)
        {
            max = sum;
            mins = a[i].xm;
        }
```