提交 5d9c0389 编写于 作者: W WenmuZhou

merge upstream

上级 2c8ba6a9
......@@ -203,7 +203,12 @@ def draw_ocr(image,
return image
def draw_ocr_box_txt(image, boxes, txts):
def draw_ocr_box_txt(image,
boxes,
txts,
scores=None,
drop_score=0.5,
font_path="./doc/simfang.ttf"):
h, w = image.height, image.width
img_left = image.copy()
img_right = Image.new('RGB', (w, h), (255, 255, 255))
......@@ -213,7 +218,9 @@ def draw_ocr_box_txt(image, boxes, txts):
random.seed(0)
draw_left = ImageDraw.Draw(img_left)
draw_right = ImageDraw.Draw(img_right)
for (box, txt) in zip(boxes, txts):
for idx, (box, txt) in enumerate(zip(boxes, txts)):
if scores is not None and scores[idx] < drop_score:
continue
color = (random.randint(0, 255), random.randint(0, 255),
random.randint(0, 255))
draw_left.polygon(box, fill=color)
......@@ -229,8 +236,7 @@ def draw_ocr_box_txt(image, boxes, txts):
1])**2)
if box_height > 2 * box_width:
font_size = max(int(box_width * 0.9), 10)
font = ImageFont.truetype(
"./doc/simfang.ttf", font_size, encoding="utf-8")
font = ImageFont.truetype(font_path, font_size, encoding="utf-8")
cur_y = box[0][1]
for c in txt:
char_size = font.getsize(c)
......@@ -239,8 +245,7 @@ def draw_ocr_box_txt(image, boxes, txts):
cur_y += char_size[1]
else:
font_size = max(int(box_height * 0.8), 10)
font = ImageFont.truetype(
"./doc/simfang.ttf", font_size, encoding="utf-8")
font = ImageFont.truetype(font_path, font_size, encoding="utf-8")
draw_right.text(
[box[0][0], box[0][1]], txt, fill=(0, 0, 0), font=font)
img_left = Image.blend(image, img_left, 0.5)
......@@ -255,7 +260,6 @@ def str_count(s):
Count the number of Chinese characters,
a single English character and a single number
equal to half the length of Chinese characters.
args:
s(string): the input of string
return(int):
......@@ -290,7 +294,6 @@ def text_visual(texts,
img_w(int): the width of blank img
font_path: the path of font which is used to draw text
return(array):
"""
if scores is not None:
assert len(texts) == len(
......
Markdown is supported
0% .
You are about to add 0 people to the discussion. Proceed with caution.
先完成此消息的编辑!
想要评论请 注册