未验证 提交 a4a34b24 编写于 作者: A Ankur Chauhan 提交者: GitHub

MSSQL script update (#4243)

上级 cbcd5521
......@@ -212,4 +212,10 @@ alter table ACT_RU_EXECUTION add ID_LINK_COUNT_ int;
update ACT_GE_PROPERTY set VALUE_ = '6.0.0.2' where NAME_ = 'schema.version';
update ACT_RU_EXECUTION as exe set START_USER_ID_ = (select START_USER_ID_ from ACT_HI_PROCINST where PROC_INST_ID_=exe.PROC_INST_ID_);
UPDATE outerTable
SET START_USER_ID_ = innerTable.START_USER_ID_
FROM ACT_RU_EXECUTION outerTable
INNER JOIN
(
select START_USER_ID_, PROC_INST_ID_ from ACT_HI_PROCINST
) innerTable ON outerTable.PROC_INST_ID_ = innerTable.PROC_INST_ID_;
Markdown is supported
0% .
You are about to add 0 people to the discussion. Proceed with caution.
先完成此消息的编辑!
想要评论请 注册