已验证 提交 f5d3d59d 编写于 作者: xurime's avatar xurime

ref #65: new formula function EOMONTH

上级 980fffa2
......@@ -435,6 +435,7 @@ type formulaFuncs struct {
// EFFECT
// EDATE
// ENCODEURL
// EOMONTH
// ERF
// ERF.PRECISE
// ERFC
......@@ -12394,7 +12395,9 @@ func (fn *formulaFuncs) EDATE(argsList *list.List) formulaArg {
if month.Number > 11 {
y += int(math.Floor(float64(m) / 12))
}
m = int(math.Mod(float64(m), 12))
if m = m % 12; m < 0 {
m += 12
}
if d > 28 {
if days := getDaysInMonth(y, m); d > days {
d = days
......@@ -12404,6 +12407,55 @@ func (fn *formulaFuncs) EDATE(argsList *list.List) formulaArg {
return newNumberFormulaArg(result)
}
// EOMONTH function returns the last day of the month, that is a specified
// number of months before or after an initial supplied start date. The syntax
// of the function is:
//
// EOMONTH(start_date,months)
//
func (fn *formulaFuncs) EOMONTH(argsList *list.List) formulaArg {
if argsList.Len() != 2 {
return newErrorFormulaArg(formulaErrorVALUE, "EOMONTH requires 2 arguments")
}
date := argsList.Front().Value.(formulaArg)
num := date.ToNumber()
var dateTime time.Time
if num.Type != ArgNumber {
dateString := strings.ToLower(date.Value())
if !isDateOnlyFmt(dateString) {
if _, _, _, _, _, err := strToTime(dateString); err.Type == ArgError {
return err
}
}
y, m, d, _, err := strToDate(dateString)
if err.Type == ArgError {
return err
}
dateTime = time.Date(y, time.Month(m), d, 0, 0, 0, 0, time.Now().Location())
} else {
if num.Number < 0 {
return newErrorFormulaArg(formulaErrorNUM, formulaErrorNUM)
}
dateTime = timeFromExcelTime(num.Number, false)
}
months := argsList.Back().Value.(formulaArg).ToNumber()
if months.Type != ArgNumber {
return months
}
y, m := dateTime.Year(), int(dateTime.Month())+int(months.Number)-1
if m < 0 {
y -= int(math.Ceil(-1 * float64(m) / 12))
}
if m > 11 {
y += int(math.Floor(float64(m) / 12))
}
if m = m % 12; m < 0 {
m += 12
}
result, _ := timeToExcelTime(time.Date(y, time.Month(m+1), getDaysInMonth(y, m+1), 0, 0, 0, 0, time.UTC), false)
return newNumberFormulaArg(result)
}
// HOUR function returns an integer representing the hour component of a
// supplied Excel time. The syntax of the function is:
//
......
......@@ -1479,6 +1479,11 @@ func TestCalcCellValue(t *testing.T) {
"=EDATE(\"01/01/2021\",-1)": "44166",
"=EDATE(\"01/31/2020\",1)": "43890",
"=EDATE(\"01/29/2020\",12)": "44225",
"=EDATE(\"6/12/2021\",-14)": "43933",
// EOMONTH
"=EOMONTH(\"01/01/2021\",-1)": "44196",
"=EOMONTH(\"01/29/2020\",12)": "44227",
"=EOMONTH(\"01/12/2021\",-18)": "43677",
// HOUR
"=HOUR(1)": "0",
"=HOUR(43543.5032060185)": "12",
......@@ -3447,6 +3452,12 @@ func TestCalcCellValue(t *testing.T) {
"=EDATE(-1,0)": "#NUM!",
"=EDATE(\"\",0)": "#VALUE!",
"=EDATE(\"January 25, 100\",0)": "#VALUE!",
// EOMONTH
"=EOMONTH()": "EOMONTH requires 2 arguments",
"=EOMONTH(0,\"\")": "strconv.ParseFloat: parsing \"\": invalid syntax",
"=EOMONTH(-1,0)": "#NUM!",
"=EOMONTH(\"\",0)": "#VALUE!",
"=EOMONTH(\"January 25, 100\",0)": "#VALUE!",
// HOUR
"=HOUR()": "HOUR requires exactly 1 argument",
"=HOUR(-1)": "HOUR only accepts positive argument",
......
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