提交 cc14600c 编写于 作者: F Filipe Manana 提交者: David Sterba

btrfs: make checksum item extension more efficient

When we want to add checksums into the checksums tree, or a log tree, we
try whenever possible to extend existing checksum items, as this helps
reduce amount of metadata space used, since adding a new item uses extra
metadata space for a btrfs_item structure (25 bytes).

However we have two inefficiencies in the current approach:

1) After finding a checksum item that covers a range with an end offset
   that matches the start offset of the checksum range we want to insert,
   we release the search path populated by btrfs_lookup_csum() and then
   do another COW search on tree with the goal of getting additional
   space for at least one checksum. Doing this path release and then
   searching again is a waste of time because very often the leaf already
   has enough free space for at least one more checksum;

2) After the COW search that guarantees we get free space in the leaf for
   at least one more checksum, we end up not doing the extension of the
   previous checksum item, and fallback to insertion of a new checksum
   item, if the leaf doesn't have an amount of free space larger then the
   space required for 2 checksums plus one btrfs_item structure - this is
   pointless for two reasons:

   a) We want to extend an existing item, so we don't need to account for
      a btrfs_item structure (25 bytes);

   b) We made the COW search with an insertion size for 1 single checksum,
      so if the leaf ends up with a free space amount smaller then 2
      checksums plus the size of a btrfs_item structure, we give up on the
      extension of the existing item and jump to the 'insert' label, where
      we end up releasing the path and then doing yet another search to
      insert a new checksum item for a single checksum.

Fix these inefficiencies by doing the following:

- For case 1), before releasing the path just check if the leaf already
  has enough space for at least 1 more checksum, and if it does, jump
  directly to the item extension code, with releasing our current path,
  which was already COWed by btrfs_lookup_csum();

- For case 2), fix the logic so that for item extension we require only
  that the leaf has enough free space for 1 checksum, and not a minimum
  of 2 checksums plus space for a btrfs_item structure.
Signed-off-by: NFilipe Manana <fdmanana@suse.com>
Signed-off-by: NDavid Sterba <dsterba@suse.com>
上级 e289f03e
......@@ -907,9 +907,22 @@ int btrfs_csum_file_blocks(struct btrfs_trans_handle *trans,
}
/*
* at this point, we know the tree has an item, but it isn't big
* enough yet to put our csum in. Grow it
* At this point, we know the tree has a checksum item that ends at an
* offset matching the start of the checksum range we want to insert.
* We try to extend that item as much as possible and then add as many
* checksums to it as they fit.
*
* First check if the leaf has enough free space for at least one
* checksum. If it has go directly to the item extension code, otherwise
* release the path and do a search for insertion before the extension.
*/
if (btrfs_leaf_free_space(leaf) >= csum_size) {
btrfs_item_key_to_cpu(leaf, &found_key, path->slots[0]);
csum_offset = (bytenr - found_key.offset) >>
fs_info->sb->s_blocksize_bits;
goto extend_csum;
}
btrfs_release_path(path);
ret = btrfs_search_slot(trans, root, &file_key, path,
csum_size, 1);
......@@ -933,19 +946,13 @@ int btrfs_csum_file_blocks(struct btrfs_trans_handle *trans,
goto insert;
}
extend_csum:
if (csum_offset == btrfs_item_size_nr(leaf, path->slots[0]) /
csum_size) {
int extend_nr;
u64 tmp;
u32 diff;
u32 free_space;
if (btrfs_leaf_free_space(leaf) <
sizeof(struct btrfs_item) + csum_size * 2)
goto insert;
free_space = btrfs_leaf_free_space(leaf) -
sizeof(struct btrfs_item) - csum_size;
tmp = sums->len - total_bytes;
tmp >>= fs_info->sb->s_blocksize_bits;
WARN_ON(tmp < 1);
......@@ -956,7 +963,7 @@ int btrfs_csum_file_blocks(struct btrfs_trans_handle *trans,
MAX_CSUM_ITEMS(fs_info, csum_size) * csum_size);
diff = diff - btrfs_item_size_nr(leaf, path->slots[0]);
diff = min(free_space, diff);
diff = min_t(u32, btrfs_leaf_free_space(leaf), diff);
diff /= csum_size;
diff *= csum_size;
......
Markdown is supported
0% .
You are about to add 0 people to the discussion. Proceed with caution.
先完成此消息的编辑!
想要评论请 注册