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体验新版 GitCode,发现更多精彩内容 >>
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ad477b91
编写于
10月 11, 2017
作者:
Y
Yancey1989
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差异文件
update
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e880a356
变更
2
隐藏空白更改
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并排
Showing
2 changed file
with
17 addition
and
15 deletion
+17
-15
paddle/operators/sequence_concat_op.cc
paddle/operators/sequence_concat_op.cc
+5
-0
paddle/operators/sequence_concat_op.h
paddle/operators/sequence_concat_op.h
+12
-15
未找到文件。
paddle/operators/sequence_concat_op.cc
浏览文件 @
ad477b91
...
...
@@ -75,17 +75,22 @@ class SequenceConcatOpMaker : public framework::OpProtoAndCheckerMaker {
If the axis is other than 0(here, axis is 1 and level is 1),
each input should have the same LoD information and the LoD
information of the output keeps the same as the input.
LoD(x0) = {{0,2,4}, {0,1,2,3,4}}; Dims(x0) = (4,3,4)
LoD(x1) = {{0,2,4}, {0,1,2,3,4}}; Dims(x1) = (4,4,4)
LoD(Out) = {{0,2,4}, {0,1,2,3,4}}; Dims(Out) = (4,7,4)
- Case2:
If the axis is 0(here, leve is 0), the inputs are concatenated along
time steps, the LoD information of the output need to re-compute.
LoD(x0) = {{0,2,4}, {0,1,2,3,4}}; Dims(x0) = (4,3,4)
LoD(x1) = {{0,3,5}, {0,1,2,3,5}}; Dims(x1) = (5,3,4)
LoD(Out) = {{0,5,9}, {0,1,2,3,4,5,6,7,9}}; Dims(Out) = (9,3,4)
- Case3:
If the axis is 0(here, level is 1).
LoD(x0) = {{0,2,4}, {0,1,2,3,4}}; Dims(x0) = (4,3,4)
LoD(x1) = {{0,3,5}, {0,1,3,4,5}}; Dims(x1) = (5,3,4)
LoD(Out) = {{0,5,9}, {0,2,5,7,9}}; Dims(Out) = (9,3,4)
...
...
paddle/operators/sequence_concat_op.h
浏览文件 @
ad477b91
...
...
@@ -29,22 +29,19 @@ LoD concatLoD(const std::vector<const T*> ins, const size_t axis,
auto
out_lod
=
ins
[
0
]
->
lod
();
const
size_t
n
=
ins
.
size
();
if
(
axis
==
0UL
)
{
if
(
level
==
0UL
)
{
for
(
size_t
i
=
1
;
i
<
n
;
++
i
)
{
for
(
size_t
j
=
0
;
j
<
ins
[
i
]
->
lod
()[
0
].
size
();
++
j
)
{
out_lod
[
0
][
j
]
+=
ins
[
i
]
->
lod
()[
0
][
j
];
}
for
(
size_t
i
=
1
;
i
<
n
;
++
i
)
{
for
(
size_t
j
=
0
;
j
<
ins
[
i
]
->
lod
()[
0
].
size
();
++
j
)
{
out_lod
[
0
][
j
]
+=
ins
[
i
]
->
lod
()[
0
][
j
];
}
}
else
if
(
level
==
1UL
)
{
PADDLE_ENFORCE_EQ
(
ins
[
0
]
->
NumLevels
(),
2UL
,
"If the level is 1, all of the inputs "
"should be the nested sequence."
);
for
(
size_t
i
=
1
;
i
<
n
;
++
i
)
{
for
(
size_t
j
=
0
;
j
<
ins
[
i
]
->
lod
()[
0
].
size
();
++
j
)
{
out_lod
[
0
].
push_back
(
ins
[
i
]
->
lod
()[
0
][
j
]);
}
for
(
size_t
j
=
0
;
j
<
ins
[
i
]
->
lod
()[
1
].
size
();
++
j
)
{
out_lod
[
1
][
j
]
+=
ins
[
i
]
->
lod
()[
1
][
j
];
if
(
ins
[
0
]
->
NumLevels
()
==
2
)
{
for
(
size_t
j
=
1
;
j
<
ins
[
i
]
->
lod
()[
1
].
size
();
++
j
)
{
if
(
level
==
0UL
)
{
out_lod
[
1
].
push_back
(
out_lod
[
1
].
back
()
+
ins
[
i
]
->
lod
()[
1
][
j
]
-
ins
[
i
]
->
lod
()[
1
][
j
-
1
]);
}
else
if
(
level
==
1UL
)
{
out_lod
[
1
][
j
]
+=
ins
[
1
]
->
lod
()[
1
][
j
];
}
}
}
}
...
...
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