find some mistakes

notes/剑指 offer 题解.md

@@ -1778,47 +1778,46 @@ public int MoreThanHalfNum_Solution(int[] nums) {
 找到第 K 个元素之后，就可以再遍历一次数组，所有小于等于该元素的数组元素都是最小的 K 个数。
 
 ```java
-public ArrayList<Integer> GetLeastNumbers_Solution(int[] nums, int k) {
-    if (k > nums.length || k <= 0)
-        return new ArrayList<>();
-    int kthSmallest = findKthSmallest(nums, k - 1);
-    ArrayList<Integer> ret = new ArrayList<>();
-    for (int val : nums)
-        if (val <= kthSmallest && ret.size() < k)
-            ret.add(val);
-    return ret;
-}
+ public ArrayList<Integer> GetLeastNumbers_Solution(int[] input, int k) {
+        ArrayList<Integer> res = new ArrayList<>();
+        if (k > input.length || k <= 0) return res;
+        findKthSmallest(input, k - 1);
+        for (int i = 0; i < k; i++) {
+            res.add(input[i]);
+        }
+        return res;
+    }
 
-public int findKthSmallest(int[] nums, int k) {
-    int l = 0, h = nums.length - 1;
-    while (l < h) {
-        int j = partition(nums, l, h);
-        if (j == k)
-            break;
-        if (j > k)
-            h = j - 1;
-        else
-            l = j + 1;
+    private void findKthSmallest(int[] nums, int k) {
+        int l = 0, h = nums.length - 1;
+        while (l < h) {
+            int j = paration(nums, l, h);
+            if (j == k) break;
+            else if (j > k) h = j - 1;
+            else l = j + 1;
+        }
     }
-    return nums[k];
-}
 
-private int partition(int[] nums, int l, int h) {
-    int i = l, j = h + 1;
-    while (true) {
-        while (i < h && nums[++i] < nums[l]) ;
-        while (j > l && nums[l] < nums[--j]) ;
-        if (i >= j)
-            break;
-        swap(nums, i, j);
+    private int paration(int[] nums, int l, int h) {
+        //nums[l+1,i] nums[j,h]
+        int i = l, j = h + 1;
+        while (true) {
+            while (i < h && nums[++i] < nums[l]) ;
+            while (j > l + 1 && nums[--j] > nums[l]) ;
+            if (i >= j) break;
+            swap(nums, i, j);
+        }
+        swap(nums, l, j);
+        return j;
+
+
     }
-    swap(nums, l, j);
-    return j;
-}
 
-private void swap(int[] nums, int i, int j) {
-    int t = nums[i]; nums[i] = nums[j]; nums[j] = t;
-}
+    private void swap(int[] nums, int i, int j) {
+        int t = nums[i];
+        nums[i] = nums[j];
+        nums[j] = t;
+    }
 ```
 
 ### 大小为 K 的最小堆