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体验新版 GitCode,发现更多精彩内容 >>
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提交
c62c288e
编写于
4月 16, 2020
作者:
A
Artem Zuikov
提交者:
GitHub
4月 16, 2020
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电子邮件补丁
差异文件
fix COMMA and other JOIN mix (#10311)
上级
d5b3b2c7
变更
3
隐藏空白更改
内联
并排
Showing
3 changed file
with
51 addition
and
4 deletion
+51
-4
src/Interpreters/CrossToInnerJoinVisitor.cpp
src/Interpreters/CrossToInnerJoinVisitor.cpp
+8
-4
tests/queries/0_stateless/01117_comma_and_others_join_mix.reference
...ies/0_stateless/01117_comma_and_others_join_mix.reference
+23
-0
tests/queries/0_stateless/01117_comma_and_others_join_mix.sql
...s/queries/0_stateless/01117_comma_and_others_join_mix.sql
+20
-0
未找到文件。
src/Interpreters/CrossToInnerJoinVisitor.cpp
浏览文件 @
c62c288e
...
...
@@ -52,17 +52,21 @@ struct JoinedElement
void
rewriteCommaToCross
()
{
if
(
join
)
if
(
join
&&
join
->
kind
==
ASTTableJoin
::
Kind
::
Comma
)
join
->
kind
=
ASTTableJoin
::
Kind
::
Cross
;
}
void
rewriteCrossToInner
(
ASTPtr
on_expression
)
bool
rewriteCrossToInner
(
ASTPtr
on_expression
)
{
if
(
join
->
kind
!=
ASTTableJoin
::
Kind
::
Cross
)
return
false
;
join
->
kind
=
ASTTableJoin
::
Kind
::
Inner
;
join
->
strictness
=
ASTTableJoin
::
Strictness
::
All
;
join
->
on_expression
=
on_expression
;
join
->
children
.
push_back
(
join
->
on_expression
);
return
true
;
}
ASTPtr
arrayJoin
()
const
{
return
element
.
array_join
;
}
...
...
@@ -329,8 +333,8 @@ void CrossToInnerJoinMatcher::visit(ASTSelectQuery & select, ASTPtr &, Data & da
{
if
(
visitor_data
.
matchAny
(
i
))
{
joined_tables
[
i
].
rewriteCrossToInner
(
visitor_data
.
makeOnExpression
(
i
));
data
.
done
=
true
;
if
(
joined_tables
[
i
].
rewriteCrossToInner
(
visitor_data
.
makeOnExpression
(
i
)))
data
.
done
=
true
;
}
}
}
...
...
tests/queries/0_stateless/01117_comma_and_others_join_mix.reference
0 → 100644
浏览文件 @
c62c288e
0 0 0
0 0 1
0 0 2
0 0 3
1 1 0
1 1 1
1 1 2
1 1 3
-
0 0 0
0 1 0
1 0 1
1 1 1
2 0 \N
2 1 \N
-
0 0 0
0 1 1
0 2 2
1 0 0
1 1 1
1 2 2
\N \N 3
tests/queries/0_stateless/01117_comma_and_others_join_mix.sql
0 → 100644
浏览文件 @
c62c288e
SET
join_use_nulls
=
1
;
SELECT
*
FROM
numbers
(
2
)
AS
n1
JOIN
numbers
(
3
)
AS
n2
ON
n1
.
number
=
n2
.
number
,
numbers
(
4
)
AS
n3
ORDER
BY
n1
.
number
,
n2
.
number
,
n3
.
number
;
SELECT
'-'
;
SELECT
*
FROM
numbers
(
3
)
AS
n1
,
numbers
(
2
)
AS
n2
LEFT
JOIN
numbers
(
2
)
AS
n3
ON
n1
.
number
=
n3
.
number
ORDER
BY
n1
.
number
,
n2
.
number
,
n3
.
number
;
SELECT
'-'
;
SELECT
*
FROM
numbers
(
2
)
AS
n1
,
numbers
(
3
)
AS
n2
RIGHT
JOIN
numbers
(
4
)
AS
n3
ON
n2
.
number
=
n3
.
number
ORDER
BY
n1
.
number
,
n2
.
number
,
n3
.
number
;
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