提交 2468057d 编写于 作者: M minqiyang

Move code to SumSeqPoolGradFunctor

test=develop
上级 9725db0d
......@@ -157,6 +157,31 @@ class FirstSeqPoolFunctor {
}
};
template <typename T>
class SumSeqPoolGradFunctor {
public:
void operator()(const platform::CPUDeviceContext& context,
const framework::Tensor& out_grad,
framework::LoDTensor* in_grad) {
auto lod = in_grad->lod()[0];
int64_t out_w = out_grad.numel() / out_grad.dims()[0];
int64_t in_w = in_grad->numel() / in_grad->dims()[0];
PADDLE_ENFORCE(in_w == out_w);
const T* out_g_data = out_grad.data<T>();
T* in_g_data = in_grad->mutable_data<T>(context.GetPlace());
auto blas = math::GetBlas<platform::CPUDeviceContext, T>(context);
for (int i = 0; i < static_cast<int>(lod.size()) - 1; ++i) {
int64_t h = static_cast<int64_t>(lod[i + 1] - lod[i]);
int64_t in_offset = lod[i] * in_w;
const T* out_pos = out_g_data + i * out_w;
T* in_pos = in_g_data + in_offset;
for (int r = 0; r != h; ++r) {
blas.VCOPY(in_w, out_pos, in_pos + r * in_w);
}
}
}
};
template <typename T>
class SequencePoolFunctor<platform::CPUDeviceContext, T> {
public:
......@@ -233,23 +258,8 @@ class SequencePoolGradFunctor<platform::CPUDeviceContext, T> {
}
if (pooltype == "SUM") {
auto lod = in_grad->lod()[0];
int64_t out_w = out_grad.numel() / out_grad.dims()[0];
int64_t in_w = in_grad->numel() / in_grad->dims()[0];
PADDLE_ENFORCE(in_w == out_w);
const T* out_g_data = out_grad.data<T>();
T* in_g_data = in_grad->mutable_data<T>(context.GetPlace());
auto blas = math::GetBlas<platform::CPUDeviceContext, T>(context);
for (int i = 0; i < static_cast<int>(lod.size()) - 1; ++i) {
int64_t h = static_cast<int64_t>(lod[i + 1] - lod[i]);
int64_t in_offset = lod[i] * in_w;
const T* out_pos = out_g_data + i * out_w;
T* in_pos = in_g_data + in_offset;
for (int r = 0; r != h; ++r) {
blas.VCOPY(in_w, out_pos, in_pos + r * in_w);
}
}
math::SumSeqPoolGradFunctor<T> sum_pool_grad;
sum_pool_grad(context, out_grad, in_grad);
return;
}
......
Markdown is supported
0% .
You are about to add 0 people to the discussion. Proceed with caution.
先完成此消息的编辑!
想要评论请 注册