---
title: Math Sample
subtitle: Using KaTeX
date: 2017-03-05
tags: ["example", "math"]
---

KaTeX can be used to generate complex math formulas. It supports in-line math using the `\\( ... \\)` delimiters, like this: \\( E = mc^2 \\). By default, it does *not* support in-line delimiters `$...$` because those occur too commonly in typical webpages. It supports displayed math using the `$$` or `\\[...\\]` delimiters, like this:

Formula 1:
$$
\phi = \frac{(1+\sqrt{5})}{2} = 1.6180339887\cdots
$$

Formula 2: (same formula, different delimiter)
\\[
\phi = \frac{(1+\sqrt{5})}{2} = 1.6180339887\cdots
\\]

Additional details can be found on [GitHub](https://github.com/Khan/KaTeX) or on the [Wiki](http://tiddlywiki.com/plugins/tiddlywiki/katex/).
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### Example 1

If the text between $$ contains newlines it will rendered in display mode:
```
$$
f(x) = \int_{-\infty}^\infty\hat f(\xi)\,e^{2 \pi i \xi x}\,d\xi
$$
```
$$
f(x) = \int_{-\infty}^\infty\hat f(\xi)\,e^{2 \pi i \xi x}\,d\xi
$$


### Example 2
```
$$
\frac{1}{\Bigl(\sqrt{\phi \sqrt{5}}-\phi\Bigr) e^{\frac25 \pi}} = 1+\frac{e^{-2\pi}} {1+\frac{e^{-4\pi}} {1+\frac{e^{-6\pi}} {1+\frac{e^{-8\pi}} {1+\cdots} } } }
$$
```
$$
\frac{1}{\Bigl(\sqrt{\phi \sqrt{5}}-\phi\Bigr) e^{\frac25 \pi}} = 1+\frac{e^{-2\pi}} {1+\frac{e^{-4\pi}} {1+\frac{e^{-6\pi}} {1+\frac{e^{-8\pi}} {1+\cdots} } } }
$$


### Example 3
```
$$
1 +  \frac{q^2}{(1-q)}+\frac{q^6}{(1-q)(1-q^2)}+\cdots = \prod_{j=0}^{\infty}\frac{1}{(1-q^{5j+2})(1-q^{5j+3})}, \quad\quad \text{for }\lvert q\rvert<1.
$$
```
$$
1 +  \frac{q^2}{(1-q)}+\frac{q^6}{(1-q)(1-q^2)}+\cdots = \prod_{j=0}^{\infty}\frac{1}{(1-q^{5j+2})(1-q^{5j+3})}, \quad\quad \text{for }\lvert q\rvert<1.
$$

### Example 4

Remember, certain characters are rendered by markdown, so you may need to workaround those issues. You can find the complete list of KaTeX supported functions here: [https://khan.github.io/KaTeX/docs/supported.html](https://khan.github.io/KaTeX/docs/supported.html)

For example, the `'` character can  be replaced with `^\prime`:

$$
G^\prime = G - u
$$

The `"` character can  be replaced with `^{\prime\prime}`:

$$
G^{\prime\prime} = G^\prime - v
$$