提交 b443ee9c 编写于 作者: Z zhangyadong.zhangy

🐛 解决后端table搜索框未传keywords的问题

上级 8f7a7ffa
......@@ -207,6 +207,8 @@ Table.prototype = {
data2 = data[i].split('=');
parameter[data2[0]] = data2[1];
}
params = $.extend({}, params);
params.keywords = params.searchText;
return {
...parameter, ...params
};
......
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