提交 f4fa20e3 编写于 作者: S Shengliang Guan

test: valgrind case

上级 6a8c1e4f
...@@ -105,6 +105,40 @@ sql select * from stb where tbcol + 3 <> null; ...@@ -105,6 +105,40 @@ sql select * from stb where tbcol + 3 <> null;
print =============== step5: explain print =============== step5: explain
print =============== check
$null=
system_content sh/checkValgrind.sh -n dnode1
print cmd return result ----> [ $system_content ]
if $system_content > 0 then
return -1
endi
if $system_content == $null then
return -1
endi
print =============== restart
system sh/exec.sh -n dnode1 -s stop -x SIGINT
system sh/exec.sh -n dnode1 -s start -v
sql select avg(tbcol) as c from stb
sql select avg(tbcol) as c from stb where ts <= 1601481840000
sql select avg(tbcol) as c from stb where tgcol < 5 and ts <= 1601481840000
sql select avg(tbcol) as c from stb interval(1m)
sql select avg(tbcol) as c from stb interval(1d)
sql select avg(tbcol) as b from stb where ts <= 1601481840000 interval(1m)
sql select avg(tbcol) as c from stb group by tgcol
sql select avg(tbcol) as b from stb where ts <= 1601481840000 partition by tgcol interval(1m)
sql show table distributed stb
sql select count(tbcol) as b from stb where ts <= 1601481840000 partition by tgcol interval(1m)
sql select diff(tbcol) from stb where ts <= 1601481840000
sql select first(tbcol), last(tbcol) as c from stb group by tgcol
sql select first(tbcol), last(tbcol) as b from stb where ts <= 1601481840000 and tbcol2 is null partition by tgcol interval(1m)
sql select first(tbcol), last(tbcol) as b from stb where ts <= 1601481840000 partition by tgcol interval(1m)
sql select count(tbcol), avg(tbcol), max(tbcol), min(tbcol), sum(tbcol), stddev(tbcol) from stb where ts <= 1601481840000 partition by tgcol interval(1m)
sql select last_row(tbcol), stddev(tbcol) from stb where tbcol > 5 and tbcol < 20 group by tgcol
_OVER: _OVER:
system sh/exec.sh -n dnode1 -s stop -x SIGINT system sh/exec.sh -n dnode1 -s stop -x SIGINT
print =============== check print =============== check
......
Markdown is supported
0% .
You are about to add 0 people to the discussion. Proceed with caution.
先完成此消息的编辑!
想要评论请 注册