提交 ebe8192d 编写于 作者: H Haojun Liao

refactor(query): do some internal refactor.

上级 c7b511ed
...@@ -88,7 +88,7 @@ static int32_t getExprFunctionId(SExprInfo* pExprInfo) { ...@@ -88,7 +88,7 @@ static int32_t getExprFunctionId(SExprInfo* pExprInfo) {
static void doSetTagValueToResultBuf(char* output, const char* val, int16_t type, int16_t bytes); static void doSetTagValueToResultBuf(char* output, const char* val, int16_t type, int16_t bytes);
static void setBlockStatisInfo(SqlFunctionCtx* pCtx, SExprInfo* pExpr, SSDataBlock* pSDataBlock); static void setBlockSMAInfo(SqlFunctionCtx* pCtx, SExprInfo* pExpr, SSDataBlock* pSDataBlock);
static void releaseQueryBuf(size_t numOfTables); static void releaseQueryBuf(size_t numOfTables);
...@@ -433,7 +433,7 @@ static void doSetInputDataBlockInfo(SOperatorInfo* pOperator, SqlFunctionCtx* pC ...@@ -433,7 +433,7 @@ static void doSetInputDataBlockInfo(SOperatorInfo* pOperator, SqlFunctionCtx* pC
for (int32_t i = 0; i < pOperator->exprSupp.numOfExprs; ++i) { for (int32_t i = 0; i < pOperator->exprSupp.numOfExprs; ++i) {
pCtx[i].order = order; pCtx[i].order = order;
pCtx[i].input.numOfRows = pBlock->info.rows; pCtx[i].input.numOfRows = pBlock->info.rows;
setBlockStatisInfo(&pCtx[i], &pOperator->exprSupp.pExprInfo[i], pBlock); setBlockSMAInfo(&pCtx[i], &pOperator->exprSupp.pExprInfo[i], pBlock);
pCtx[i].pSrcBlock = pBlock; pCtx[i].pSrcBlock = pBlock;
} }
} }
...@@ -799,7 +799,7 @@ static int32_t doCreateConstantValColumnAggInfo(SInputColumnInfoData* pInput, SF ...@@ -799,7 +799,7 @@ static int32_t doCreateConstantValColumnAggInfo(SInputColumnInfoData* pInput, SF
return TSDB_CODE_SUCCESS; return TSDB_CODE_SUCCESS;
} }
void setBlockStatisInfo(SqlFunctionCtx* pCtx, SExprInfo* pExprInfo, SSDataBlock* pBlock) { void setBlockSMAInfo(SqlFunctionCtx* pCtx, SExprInfo* pExprInfo, SSDataBlock* pBlock) {
int32_t numOfRows = pBlock->info.rows; int32_t numOfRows = pBlock->info.rows;
SInputColumnInfoData* pInput = &pCtx->input; SInputColumnInfoData* pInput = &pCtx->input;
......
Markdown is supported
0% .
You are about to add 0 people to the discussion. Proceed with caution.
先完成此消息的编辑!
想要评论请 注册