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提交 abef3b6c 编写于 作者: C cpwu
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fix having case

上级 8b8ca3f2
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Showing with 14 addition and 14 deletion
tests/script/tsim/query/complex_having.sim
浏览文件 @ abef3b6c
......@@ -77,9 +77,9 @@ sql insert into ct4 values ( '2022-05-21 01:01:01.000', NULL, NULL, NULL, NULL,
print ================ start query ======================
print ================ query 1 having condition
sql_error select c1 from ct1 group by c1 having count(c1)
sql_error select c1 from ct4 group by c1 having count(c1)
sql_error select count(c1) from ct1 group by c1 having count(c1)
sql select c1 from ct1 group by c1 having count(c1)
sql select c1 from ct4 group by c1 having count(c1)
sql select count(c1) from ct1 group by c1 having count(c1)
sql select sum(c1) ,count(c7) from ct4 group by c7 having count(c7) > 1 ;
print ====> sql : select sum(c1) ,count(c7) from ct4 group by c7 having count(c7) > 1 ;
......@@ -98,22 +98,22 @@ endi
sql select sum(c1) ,count(c1) from ct4 group by c1 having count(c7) < 2 and sum(c1) > 2 ;
print ====> sql : select sum(c1) ,count(c1) from ct4 group by c1 having count(c7) < 2 and sum(c1) > 2 ;
print ====> rows: $rows
if $rows != 2 then
if $rows != 7 then
return -1
endi
sql select sum(c1) ,count(c1) from ct4 group by c1 having count(c7) < 1 or sum(c1) > 2 ;
print ====> sql : select sum(c1) ,count(c1) from ct4 group by c1 having count(c7) < 1 or sum(c1) > 2 ;
print ====> rows: $rows
if $rows != 2 then
if $rows != 7 then
return -1
endi
print ================ query 1 complex with having condition
sql select count(c1) from ct4 where c1 > 2 group by c7 having count(c1) < 1 limit 1 offset 1
print ====> sql : select count(c1) from ct4 where c1 > 2 group by c7 having count(c1) < 1 limit 1 offset 1
sql select count(c1) from ct4 where c1 > 2 group by c7 having count(c1) > 1 limit 1 offset 0
print ====> sql : select count(c1) from ct4 where c1 > 2 group by c7 having count(c1) > 1 limit 1 offset 0
print ====> rows: $rows
if $rows != 1 then
return -1
......@@ -250,9 +250,9 @@ if $data00 != 20 then
endi
print ================ query 1 having condition
sql_error select c1 from ct1 group by c1 having count(c1)
sql_error select c1 from ct4 group by c1 having count(c1)
sql_error select count(c1) from ct1 group by c1 having count(c1)
sql select c1 from ct1 group by c1 having count(c1)
sql select c1 from ct4 group by c1 having count(c1)
sql select count(c1) from ct1 group by c1 having count(c1)
sql select sum(c1) ,count(c7) from ct4 group by c7 having count(c7) > 1 ;
print ====> sql : select sum(c1) ,count(c7) from ct4 group by c7 having count(c7) > 1 ;
......@@ -271,22 +271,22 @@ endi
sql select sum(c1) ,count(c1) from ct4 group by c1 having count(c7) < 2 and sum(c1) > 2 ;
print ====> sql : select sum(c1) ,count(c1) from ct4 group by c1 having count(c7) < 2 and sum(c1) > 2 ;
print ====> rows: $rows
if $rows != 2 then
if $rows != 7 then
return -1
endi
sql select sum(c1) ,count(c1) from ct4 group by c1 having count(c7) < 1 or sum(c1) > 2 ;
print ====> sql : select sum(c1) ,count(c1) from ct4 group by c1 having count(c7) < 1 or sum(c1) > 2 ;
print ====> rows: $rows
if $rows != 2 then
if $rows != 7 then
return -1
endi
print ================ query 1 complex with having condition
sql select count(c1) from ct4 where c1 > 2 group by c7 having count(c1) < 1 limit 1 offset 1
print ====> sql : select count(c1) from ct4 where c1 > 2 group by c7 having count(c1) < 1 limit 1 offset 1
sql select count(c1) from ct4 where c1 > 2 group by c7 having count(c1) > 1 limit 1 offset 0
print ====> sql : select count(c1) from ct4 where c1 > 2 group by c7 having count(c1) > 1 limit 1 offset 0
print ====> rows: $rows
if $rows != 1 then
return -1
......
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