提交 041ecaa3 编写于 作者: X Xiaoyu Wang

fix: some problems of parser and planner

上级 dc1b390a
......@@ -25,15 +25,15 @@ sql insert into tb3 values (now, 3, "Hash (cost=229.20..229.20 rows=101 width=2
sql create table tb4 using st1 tags(4);
sql insert into tb4 values (now, 4, "Bitmap Heap Scan on tenk1 t1 (cost=5.07..229.20 rows=101 width=244) (actual time=0.080..0.526 rows=100 loops=1)");
sql create table tb1 using st2 tags(1);
sql insert into tb1 values (now, 1, "Hash Join (cost=230.47..713.98 rows=101 width=488) (actual time=0.711..7.427 rows=100 loops=1)");
#sql create table tb1 using st2 tags(1);
#sql insert into tb1 values (now, 1, "Hash Join (cost=230.47..713.98 rows=101 width=488) (actual time=0.711..7.427 rows=100 loops=1)");
sql create table tb2 using st2 tags(2);
sql insert into tb2 values (now, 2, "Seq Scan on tenk2 t2 (cost=0.00..445.00 rows=10000 width=244) (actual time=0.007..2.583 rows=10000 loops=1)");
sql create table tb3 using st2 tags(3);
sql insert into tb3 values (now, 3, "Hash (cost=229.20..229.20 rows=101 width=244) (actual time=0.659..0.659 rows=100 loops=1)");
sql create table tb4 using st2 tags(4);
sql insert into tb4 values (now, 4, "Bitmap Heap Scan on tenk1 t1 (cost=5.07..229.20 rows=101 width=244) (actual time=0.080..0.526 rows=100 loops=1)");
#sql create table tb2 using st2 tags(2);
#sql insert into tb2 values (now, 2, "Seq Scan on tenk2 t2 (cost=0.00..445.00 rows=10000 width=244) (actual time=0.007..2.583 rows=10000 loops=1)");
#sql create table tb3 using st2 tags(3);
#sql insert into tb3 values (now, 3, "Hash (cost=229.20..229.20 rows=101 width=244) (actual time=0.659..0.659 rows=100 loops=1)");
#sql create table tb4 using st2 tags(4);
#sql insert into tb4 values (now, 4, "Bitmap Heap Scan on tenk1 t1 (cost=5.07..229.20 rows=101 width=244) (actual time=0.080..0.526 rows=100 loops=1)");
print ======== step2
......
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