提交 66ae0a8c 编写于 作者: Y yangyaming

Enhence shrink_rnn_memory_op.

上级 25af35d8
......@@ -46,8 +46,19 @@ class ShrinkRNNMemoryOp : public ArrayOp {
auto *out_var = scope.FindVar(Output("Out"));
PADDLE_ENFORCE(out_var != nullptr, "Output Out must be set");
auto &out_tensor = *out_var->GetMutable<framework::LoDTensor>();
// should consider multiple levels
size_t height = dst_num_rows;
auto lod_level = lod_rank_table.level();
if (x_tensor.lod().size() > lod_level &&
x_tensor.lod()[lod_level].size() < dst_num_rows) {
auto lod_offset = framework::GetSubLoDAndAbsoluteOffset(
x_tensor.lod(), 0, dst_num_rows + 1, lod_level);
height = lod_offset.second.second;
}
if (dst_num_rows != 0) {
out_tensor.ShareDataWith(x_tensor.Slice(0, dst_num_rows));
out_tensor.ShareDataWith(x_tensor.Slice(0, height));
}
}
};
......@@ -64,11 +75,11 @@ class ShrinkRNNMemoryOpProtoMaker : public framework::OpProtoAndCheckerMaker {
AddOutput("Out", "(LoDTensor) The shrinked RNN step memory.");
AddComment(
R"DOC(
In dynamic RNN, we are able to handle sequences of different lengths.
Because of the multiple lengths, the size of each step input can be
In dynamic RNN, we are able to handle sequences of different lengths.
Because of the multiple lengths, the size of each step input can be
different, which may lead to a mismatching between the input of
the current step and the memory generated by the previous one. This
operator shrinks memory according to the size of the next step input,
the current step and the memory generated by the previous one. This
operator shrinks memory according to the size of the next step input,
to make sure that they can match each other.
)DOC");
}
......
......@@ -26,13 +26,13 @@ class TestShrinkRNNMemory(unittest.TestCase):
cpu = core.CPUPlace()
tensor = core.LoDTensor()
tensor.set_lod([[0, 2, 5, 6]])
tensor_np = numpy.random.random(size=(3, 100)).astype('float32')
tensor_np = numpy.random.random(size=(6, 100)).astype('float32')
tensor.set(tensor_np, cpu)
exe = Executor(cpu)
outs = exe.run(feed={'x': tensor}, fetch_list=[mem1, mem2, mem3])
self.assertTrue(numpy.allclose(tensor_np[0:3], outs[0]))
self.assertTrue(numpy.allclose(tensor_np[0:2], outs[1]))
self.assertTrue(numpy.allclose(tensor_np[0:1], outs[2]))
self.assertTrue(numpy.allclose(tensor_np[0:6], outs[0]))
self.assertTrue(numpy.allclose(tensor_np[0:5], outs[1]))
self.assertTrue(numpy.allclose(tensor_np[0:2], outs[2]))
mem3_mean = layers.mean(x=mem3)
append_backward(loss=mem3_mean)
......
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