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Kwan的解忧杂货铺@新空间代码工作室
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606c0ff5
编写于
7月 01, 2023
作者:
Kwan的解忧杂货铺@新空间代码工作室
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fix:提莫攻击
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0 deletion
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-0
14_刷题/day02/problem_solving_18_01.py
14_刷题/day02/problem_solving_18_01.py
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-0
14_刷题/day02/problem_solving_18_02.py
14_刷题/day02/problem_solving_18_02.py
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-0
14_刷题/day02/problem_solving_19_01.py
14_刷题/day02/problem_solving_19_01.py
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14_刷题/day02/problem_solving_19_02.py
14_刷题/day02/problem_solving_19_02.py
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-0
14_刷题/day02/problem_solving_19_03.py
14_刷题/day02/problem_solving_19_03.py
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-0
14_刷题/day02/problem_solving_20.py
14_刷题/day02/problem_solving_20.py
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-0
14_刷题/day03/problem_solving_25.py
14_刷题/day03/problem_solving_25.py
+27
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14_刷题/day03/problem_solving_26.py
14_刷题/day03/problem_solving_26.py
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-0
未找到文件。
14_刷题/day0
3
/problem_solving_18_01.py
→
14_刷题/day0
2
/problem_solving_18_01.py
浏览文件 @
606c0ff5
文件已移动
14_刷题/day0
3
/problem_solving_18_02.py
→
14_刷题/day0
2
/problem_solving_18_02.py
浏览文件 @
606c0ff5
文件已移动
14_刷题/day0
3
/problem_solving_19_01.py
→
14_刷题/day0
2
/problem_solving_19_01.py
浏览文件 @
606c0ff5
文件已移动
14_刷题/day0
3
/problem_solving_19_02.py
→
14_刷题/day0
2
/problem_solving_19_02.py
浏览文件 @
606c0ff5
文件已移动
14_刷题/day0
3
/problem_solving_19_03.py
→
14_刷题/day0
2
/problem_solving_19_03.py
浏览文件 @
606c0ff5
文件已移动
14_刷题/day0
3
/problem_solving_20.py
→
14_刷题/day0
2
/problem_solving_20.py
浏览文件 @
606c0ff5
文件已移动
14_刷题/day03/problem_solving_25.py
0 → 100644
浏览文件 @
606c0ff5
"""
最大连续 1 的个数
"""
from
typing
import
List
class
Solution
:
def
findMaxConsecutiveOnes
(
self
,
nums
:
List
[
int
])
->
int
:
"""
试试贪心算法
:param nums:
:return:
"""
res
=
0
count
=
0
for
num
in
nums
:
if
num
==
0
:
count
=
0
continue
count
+=
1
res
=
max
(
res
,
count
)
return
res
if
__name__
==
'__main__'
:
result
=
Solution
().
findMaxConsecutiveOnes
([
1
,
1
,
0
,
1
,
1
,
1
])
print
(
result
)
14_刷题/day03/problem_solving_26.py
0 → 100644
浏览文件 @
606c0ff5
"""
提莫攻击
"""
from
typing
import
List
class
Solution
:
def
findPoisonedDuration
(
self
,
timeSeries
:
List
[
int
],
duration
:
int
)
->
int
:
"""
贪心算法
:param timeSeries:
:param duration:
:return:
"""
if
not
timeSeries
:
return
0
res
=
duration
for
i
in
range
(
1
,
len
(
timeSeries
)):
# 中毒时间取最小值,当有重叠时timeSeries[i] - timeSeries[i - 1]
res
+=
min
(
duration
,
timeSeries
[
i
]
-
timeSeries
[
i
-
1
])
return
res
if
__name__
==
'__main__'
:
# result = Solution().findPoisonedDuration([1, 4], 2)
result
=
Solution
().
findPoisonedDuration
([
1
,
2
],
2
)
# 输出3
print
(
result
)
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