提交 50626046 编写于 作者: H Haojun Liao

[td-4739]<fix>: fix bug in derivative.

上级 3e928774
......@@ -3477,6 +3477,7 @@ static void tscSubqueryRetrieveCallback(void* param, TAOS_RES* tres, int code) {
if (pSql->res.code == TSDB_CODE_SUCCESS) {
(*pSql->fp)(pParentSql->param, pParentSql, pParentSql->res.numOfRows);
} else {
pParentSql->res.code = pSql->res.code;
tscAsyncResultOnError(pParentSql);
}
}
......
......@@ -3613,16 +3613,7 @@ static void deriv_function(SQLFunctionCtx *pCtx) {
qError("error input type");
}
// initial value is not set yet, all data block are null
if (!pDerivInfo->valueSet || notNullElems <= 0) {
/*
* 1. current block and blocks before are full of null
* 2. current block may be null value
*/
assert(pCtx->hasNull);
} else {
GET_RES_INFO(pCtx)->numOfRes += notNullElems;
}
GET_RES_INFO(pCtx)->numOfRes += notNullElems;
}
#define DIFF_IMPL(ctx, d, type) \
......
......@@ -1073,6 +1073,12 @@ sql insert into t0 values('2020-1-1 1:3:9', 9);
sql insert into t0 values('2020-1-1 1:4:10', 10);
sql insert into t1 values('2020-1-1 1:1:2', 2);
print ===========================>td-4739
sql select diff(val) from (select derivative(k, 1s, 0) from t1);
if $rows != 0 then
return -1
endi
sql insert into t1 values('2020-1-1 1:1:4', 20);
sql insert into t1 values('2020-1-1 1:1:6', 200);
sql insert into t1 values('2020-1-1 1:1:8', 2000);
......
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