提交 73622626 编写于 作者: F Frederic Weisbecker 提交者: Ingo Molnar

perf sched: Fix nsec to msec conversion

We are dividing a time in ns by 1e9. This is a nsec to sec
conversion. What we want is msecs. Fix it by dividing by 1e6.
Signed-off-by: NFrederic Weisbecker <fweisbec@gmail.com>
Cc: Peter Zijlstra <a.p.zijlstra@chello.nl>
Cc: Mike Galbraith <efault@gmx.de>
Cc: Paul Mackerras <paulus@samba.org>
Cc: Arnaldo Carvalho de Melo <acme@redhat.com>
Signed-off-by: NIngo Molnar <mingo@elte.hu>
上级 66685678
......@@ -1129,9 +1129,9 @@ static void output_lat_thread(struct task_atoms *atom_list)
avg = atom_list->total_lat / atom_list->nb_atoms;
printf("|%9.3f ms |%9llu | avg:%9.3f ms | max:%9.3f ms |\n",
(double)atom_list->total_runtime / 1e9,
atom_list->nb_atoms, (double)avg / 1e9,
(double)atom_list->max_lat / 1e9);
(double)atom_list->total_runtime / 1e6,
atom_list->nb_atoms, (double)avg / 1e6,
(double)atom_list->max_lat / 1e6);
}
static void __cmd_lat(void)
......@@ -1157,7 +1157,7 @@ static void __cmd_lat(void)
printf("-----------------------------------------------------------------------------------\n");
printf(" TOTAL: |%9.3f ms |%9Ld |\n",
(double)all_runtime/1e9, all_count);
(double)all_runtime/1e6, all_count);
printf("---------------------------------------------\n");
}
......
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