提交 d593ae8a 编写于 作者: A antirez

sha1.c: use standard uint32_t.

上级 c72253ec
......@@ -23,7 +23,7 @@ A million repetitions of "a"
#include <stdio.h>
#include <string.h>
#include <sys/types.h> /* for u_int*_t */
#include <stdint.h>
#include "solarisfixes.h"
#include "sha1.h"
#include "config.h"
......@@ -53,12 +53,12 @@ A million repetitions of "a"
/* Hash a single 512-bit block. This is the core of the algorithm. */
void SHA1Transform(u_int32_t state[5], const unsigned char buffer[64])
void SHA1Transform(uint32_t state[5], const unsigned char buffer[64])
{
u_int32_t a, b, c, d, e;
uint32_t a, b, c, d, e;
typedef union {
unsigned char c[64];
u_int32_t l[16];
uint32_t l[16];
} CHAR64LONG16;
#ifdef SHA1HANDSOFF
CHAR64LONG16 block[1]; /* use array to appear as a pointer */
......@@ -128,9 +128,9 @@ void SHA1Init(SHA1_CTX* context)
/* Run your data through this. */
void SHA1Update(SHA1_CTX* context, const unsigned char* data, u_int32_t len)
void SHA1Update(SHA1_CTX* context, const unsigned char* data, uint32_t len)
{
u_int32_t i, j;
uint32_t i, j;
j = context->count[0];
if ((context->count[0] += len << 3) < j)
......@@ -168,7 +168,7 @@ void SHA1Final(unsigned char digest[20], SHA1_CTX* context)
for (i = 0; i < 2; i++)
{
u_int32_t t = context->count[i];
uint32_t t = context->count[i];
int j;
for (j = 0; j < 4; t >>= 8, j++)
......
......@@ -6,12 +6,12 @@ By Steve Reid <steve@edmweb.com>
*/
typedef struct {
u_int32_t state[5];
u_int32_t count[2];
uint32_t state[5];
uint32_t count[2];
unsigned char buffer[64];
} SHA1_CTX;
void SHA1Transform(u_int32_t state[5], const unsigned char buffer[64]);
void SHA1Transform(uint32_t state[5], const unsigned char buffer[64]);
void SHA1Init(SHA1_CTX* context);
void SHA1Update(SHA1_CTX* context, const unsigned char* data, u_int32_t len);
void SHA1Update(SHA1_CTX* context, const unsigned char* data, uint32_t len);
void SHA1Final(unsigned char digest[20], SHA1_CTX* context);
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