未验证 提交 132c7fb9 编写于 作者: N Netfan 提交者: GitHub

fix: session timeout login logic error (#678)

修复超时重新登录的页面在某些逻辑下未能正确刷新数据的问题。

fix: #673
上级 9f5085c9
......@@ -65,6 +65,7 @@ export const usePermissionStore = defineStore({
setBackMenuList(list: Menu[]) {
this.backMenuList = list;
list?.length > 0 && this.setLastBuildMenuTime();
},
setLastBuildMenuTime() {
......
......@@ -6,15 +6,44 @@
</transition>
</template>
<script lang="ts">
import { defineComponent } from 'vue';
import { defineComponent, onBeforeUnmount, onMounted, ref } from 'vue';
import Login from './Login.vue';
import { useDesign } from '/@/hooks/web/useDesign';
import { useUserStore } from '/@/store/modules/user';
import { usePermissionStore } from '/@/store/modules/permission';
import { useAppStore } from '/@/store/modules/app';
import { PermissionModeEnum } from '/@/enums/appEnum';
export default defineComponent({
name: 'SessionTimeoutLogin',
components: { Login },
setup() {
const { prefixCls } = useDesign('st-login');
const userStore = useUserStore();
const permissionStore = usePermissionStore();
const appStore = useAppStore();
const userId = ref<Nullable<number | string>>(0);
const isBackMode = () => {
return appStore.getProjectConfig.permissionMode === PermissionModeEnum.BACK;
};
onMounted(() => {
// 记录当前的UserId
userId.value = userStore.getUserInfo?.userId;
console.log('Mounted', userStore.getUserInfo);
});
onBeforeUnmount(() => {
if (userId.value && userId.value !== userStore.getUserInfo.userId) {
// 登录的不是同一个用户,刷新整个页面以便丢弃之前用户的页面状态
document.location.reload();
} else if (isBackMode() && permissionStore.getLastBuildMenuTime === 0) {
// 后台权限模式下,没有成功加载过菜单,就重新加载整个页面。这通常发生在会话过期后按F5刷新整个页面后载入了本模块这种场景
document.location.reload();
}
});
return { prefixCls };
},
});
......
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