提交 dcc1cae5 编写于 作者: R Rafael França 提交者: GitHub

Merge pull request #29594 from ahazem/fix-regression-with-date-helper

Fix regression with date helper in 5.1.2 
......@@ -14,6 +14,11 @@
*Yuji Yaginuma*
* Update distance_of_time_in_words helper to display better error messages
for bad input.
*Jay Hayes*
## Rails 5.1.1 (May 12, 2017) ##
......
......@@ -95,8 +95,8 @@ def distance_of_time_in_words(from_time, to_time = 0, options = {})
scope: :'datetime.distance_in_words'
}.merge!(options)
from_time = from_time.to_time if from_time.respond_to?(:to_time)
to_time = to_time.to_time if to_time.respond_to?(:to_time)
from_time = normalize_distance_of_time_argument_to_time(from_time)
to_time = normalize_distance_of_time_argument_to_time(to_time)
from_time, to_time = to_time, from_time if from_time > to_time
distance_in_minutes = ((to_time - from_time) / 60.0).round
distance_in_seconds = (to_time - from_time).round
......@@ -130,22 +130,18 @@ def distance_of_time_in_words(from_time, to_time = 0, options = {})
# 60 days up to 365 days
when 86400...525600 then locale.t :x_months, count: (distance_in_minutes.to_f / 43200.0).round
else
if from_time.acts_like?(:time) && to_time.acts_like?(:time)
fyear = from_time.year
fyear += 1 if from_time.month >= 3
tyear = to_time.year
tyear -= 1 if to_time.month < 3
leap_years = (fyear > tyear) ? 0 : (fyear..tyear).count { |x| Date.leap?(x) }
minute_offset_for_leap_year = leap_years * 1440
# Discount the leap year days when calculating year distance.
# e.g. if there are 20 leap year days between 2 dates having the same day
# and month then the based on 365 days calculation
# the distance in years will come out to over 80 years when in written
# English it would read better as about 80 years.
minutes_with_offset = distance_in_minutes - minute_offset_for_leap_year
else
minutes_with_offset = distance_in_minutes
end
from_year = from_time.year
from_year += 1 if from_time.month >= 3
to_year = to_time.year
to_year -= 1 if to_time.month < 3
leap_years = (from_year > to_year) ? 0 : (from_year..to_year).count { |x| Date.leap?(x) }
minute_offset_for_leap_year = leap_years * 1440
# Discount the leap year days when calculating year distance.
# e.g. if there are 20 leap year days between 2 dates having the same day
# and month then the based on 365 days calculation
# the distance in years will come out to over 80 years when in written
# English it would read better as about 80 years.
minutes_with_offset = distance_in_minutes - minute_offset_for_leap_year
remainder = (minutes_with_offset % MINUTES_IN_YEAR)
distance_in_years = (minutes_with_offset.div MINUTES_IN_YEAR)
if remainder < MINUTES_IN_QUARTER_YEAR
......@@ -687,6 +683,18 @@ def time_tag(date_or_time, *args, &block)
content_tag("time".freeze, content, options.reverse_merge(datetime: datetime), &block)
end
private
def normalize_distance_of_time_argument_to_time(value)
if value.is_a?(Numeric)
Time.at(value)
elsif value.respond_to?(:to_time)
value.to_time
else
raise ArgumentError, "#{value.inspect} can't be converted to a Time value"
end
end
end
class DateTimeSelector #:nodoc:
......
......@@ -143,6 +143,16 @@ def test_distance_in_words_doesnt_use_the_quotient_operator
klass.send :public, :/
end
def test_distance_in_words_with_nil_input
assert_raises(ArgumentError) { distance_of_time_in_words(nil) }
assert_raises(ArgumentError) { distance_of_time_in_words(0, nil) }
end
def test_distance_in_words_with_mixed_argument_types
assert_equal "1 minute", distance_of_time_in_words(0, Time.at(60))
assert_equal "10 minutes", distance_of_time_in_words(Time.at(600), 0)
end
def test_time_ago_in_words_passes_include_seconds
assert_equal "less than 20 seconds", time_ago_in_words(15.seconds.ago, include_seconds: true)
assert_equal "less than a minute", time_ago_in_words(15.seconds.ago, include_seconds: false)
......
Markdown is supported
0% .
You are about to add 0 people to the discussion. Proceed with caution.
先完成此消息的编辑!
想要评论请 注册