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由 Sean Griffin 提交于
This fixes incorrect assumptions made by e991c7b8 that we can assume the DB is already casting the value for us. The enum type needs additional information to perform casting, and needs a subtype. I've opted not to call `super` in `cast`, as we have a known set of types which we accept there, and the subtype likely doesn't accept them (symbol -> integer doesn't make sense) Close #23190
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