提交 fe667e4a 编写于 作者: C Christophe Riccio

Fixed Ticket 135

上级 e306f9f6
......@@ -449,7 +449,7 @@ namespace quaternion{
Result.w = (m[1][2] - m[2][1]) * mult;
Result.x = biggestVal;
Result.y = (m[0][1] + m[1][0]) * mult;
Result.z = (m[2][1] + m[1][2]) * mult;
Result.z = (m[2][0] + m[0][2]) * mult;
break;
case 2:
Result.w = (m[2][0] - m[0][2]) * mult;
......
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