未验证 提交 7f1a1570 编写于 作者: R RedContritio 提交者: GitHub

Fix Python IndexError of case1: paddle.linalg.lstsq (#49985)

上级 3e9d8548
......@@ -278,5 +278,38 @@ class LinalgLstsqTestCaseLarge2(LinalgLstsqTestCase):
self._input_shape_2 = (50, 300)
class TestLinalgLstsqAPIError(unittest.TestCase):
def setUp(self):
pass
def test_api_errors(self):
def test_x_bad_shape():
x = paddle.to_tensor(np.random.random(size=(5)), dtype=np.float32)
y = paddle.to_tensor(
np.random.random(size=(5, 15)), dtype=np.float32
)
out = paddle.linalg.lstsq(x, y, driver='gelsy')
def test_y_bad_shape():
x = paddle.to_tensor(
np.random.random(size=(5, 10)), dtype=np.float32
)
y = paddle.to_tensor(np.random.random(size=(5)), dtype=np.float32)
out = paddle.linalg.lstsq(x, y, driver='gelsy')
def test_shape_dismatch():
x = paddle.to_tensor(
np.random.random(size=(5, 10)), dtype=np.float32
)
y = paddle.to_tensor(
np.random.random(size=(4, 15)), dtype=np.float32
)
out = paddle.linalg.lstsq(x, y, driver='gelsy')
self.assertRaises(ValueError, test_x_bad_shape)
self.assertRaises(ValueError, test_y_bad_shape)
self.assertRaises(ValueError, test_shape_dismatch)
if __name__ == '__main__':
unittest.main()
......@@ -3171,13 +3171,26 @@ def lstsq(x, y, rcond=None, driver=None, name=None):
else:
raise RuntimeError("Only support lstsq api for CPU or CUDA device.")
if x.dtype == y.dtype and x.dtype in (paddle.float32, paddle.float64):
pass
else:
if not (x.dtype == y.dtype and x.dtype in (paddle.float32, paddle.float64)):
raise ValueError(
"Only support x and y have the same dtype such as 'float32' and 'float64'."
)
if x.ndim < 2:
raise ValueError(
f"The shape of x should be (*, M, N), but received ndim is [{x.ndim} < 2]"
)
if y.ndim < 2:
raise ValueError(
f"The shape of y should be (*, M, K), but received ndim is [{y.ndim} < 2]"
)
if x.shape[-2] != y.shape[-2]:
raise ValueError(
f"x with shape (*, M = {x.shape[-2]}, N) and y with shape (*, M = {y.shape[-2]}, K) should have same M."
)
if rcond is None:
if x.dtype == paddle.float32:
rcond = 1e-7 * max(x.shape[-2], x.shape[-1])
......
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