Skip to content
体验新版
项目
组织
正在加载...
登录
切换导航
打开侧边栏
PaddlePaddle
Paddle
提交
5022ee63
P
Paddle
项目概览
PaddlePaddle
/
Paddle
1 年多 前同步成功
通知
2310
Star
20933
Fork
5423
代码
文件
提交
分支
Tags
贡献者
分支图
Diff
Issue
1423
列表
看板
标记
里程碑
合并请求
543
Wiki
0
Wiki
分析
仓库
DevOps
项目成员
Pages
P
Paddle
项目概览
项目概览
详情
发布
仓库
仓库
文件
提交
分支
标签
贡献者
分支图
比较
Issue
1,423
Issue
1,423
列表
看板
标记
里程碑
合并请求
543
合并请求
543
Pages
分析
分析
仓库分析
DevOps
Wiki
0
Wiki
成员
成员
收起侧边栏
关闭侧边栏
动态
分支图
创建新Issue
提交
Issue看板
未验证
提交
5022ee63
编写于
12月 28, 2017
作者:
Y
Yancey
提交者:
GitHub
12月 28, 2017
浏览文件
操作
浏览文件
下载
电子邮件补丁
差异文件
ThreadPool::Run interface return std::future (#7099)
* Run interface return future * delete unused comments
上级
18311767
变更
2
隐藏空白更改
内联
并排
Showing
2 changed file
with
25 addition
and
13 deletion
+25
-13
paddle/framework/threadpool.h
paddle/framework/threadpool.h
+13
-6
paddle/framework/threadpool_test.cc
paddle/framework/threadpool_test.cc
+12
-7
未找到文件。
paddle/framework/threadpool.h
浏览文件 @
5022ee63
...
...
@@ -16,6 +16,7 @@ limitations under the License. */
#include <condition_variable>
#include <functional>
#include <future>
#include <mutex>
#include <queue>
#include <thread>
...
...
@@ -25,10 +26,11 @@ limitations under the License. */
namespace
paddle
{
namespace
framework
{
typedef
std
::
function
<
void
()
>
Task
;
class
ThreadPool
{
public:
typedef
std
::
packaged_task
<
void
()
>
Task
;
typedef
std
::
function
<
void
()
>
Fun
;
/**
* @brief Get a instance of threadpool, the thread number will
* be specified as the number of hardware thread contexts
...
...
@@ -61,13 +63,18 @@ class ThreadPool {
/**
* @brief Push a function to the queue, and will be scheduled and
* executed if a thread is available.
* @param[in] Task will be pushed to the task queue.
* @param[in] Task, will be pushed to the task queue.
* @return std::future<void>, we could wait for the task finished by
* f.wait().
*/
void
Run
(
const
Task
&
fn
)
{
std
::
future
<
void
>
Run
(
const
Fun
&
fn
)
{
std
::
unique_lock
<
std
::
mutex
>
lock
(
mutex_
);
tasks_
.
push
(
fn
);
Task
task
(
std
::
bind
(
fn
));
std
::
future
<
void
>
f
=
task
.
get_future
();
tasks_
.
push
(
std
::
move
(
task
));
lock
.
unlock
();
scheduled_
.
notify_one
();
return
f
;
}
/**
...
...
@@ -110,7 +117,7 @@ class ThreadPool {
break
;
}
// pop a task from the task queue
auto
task
=
tasks_
.
front
(
);
auto
task
=
std
::
move
(
tasks_
.
front
()
);
tasks_
.
pop
();
--
available_
;
...
...
paddle/framework/threadpool_test.cc
浏览文件 @
5022ee63
...
...
@@ -20,16 +20,21 @@ limitations under the License. */
namespace
framework
=
paddle
::
framework
;
void
do_sum
(
framework
::
ThreadPool
*
pool
,
std
::
atomic
<
int
>&
sum
,
int
cnt
)
{
std
::
vector
<
std
::
future
<
void
>>
fs
;
for
(
int
i
=
0
;
i
<
cnt
;
++
i
)
{
pool
->
Run
([
&
sum
]()
{
sum
.
fetch_add
(
1
);
});
auto
f
=
pool
->
Run
([
&
sum
]()
{
sum
.
fetch_add
(
1
);
});
fs
.
push_back
(
std
::
move
(
f
));
}
for
(
auto
&
f
:
fs
)
{
f
.
wait
();
}
}
TEST
(
ThreadPool
,
ConcurrentInit
)
{
framework
::
ThreadPool
*
pool
;
int
concurrent_cnt
=
50
;
int
n
=
50
;
std
::
vector
<
std
::
thread
>
threads
;
for
(
int
i
=
0
;
i
<
concurrent_cnt
;
++
i
)
{
for
(
int
i
=
0
;
i
<
n
;
++
i
)
{
std
::
thread
t
([
&
pool
]()
{
pool
=
framework
::
ThreadPool
::
GetInstance
();
});
threads
.
push_back
(
std
::
move
(
t
));
}
...
...
@@ -38,13 +43,13 @@ TEST(ThreadPool, ConcurrentInit) {
}
}
TEST
(
ThreadPool
,
Concurrent
Start
)
{
TEST
(
ThreadPool
,
Concurrent
Run
)
{
framework
::
ThreadPool
*
pool
=
framework
::
ThreadPool
::
GetInstance
();
std
::
atomic
<
int
>
sum
(
0
);
std
::
vector
<
std
::
thread
>
threads
;
int
concurrent_cnt
=
50
;
int
n
=
50
;
// sum = (n * (n + 1)) / 2
for
(
int
i
=
1
;
i
<=
concurrent_cnt
;
++
i
)
{
for
(
int
i
=
1
;
i
<=
n
;
++
i
)
{
std
::
thread
t
(
do_sum
,
pool
,
std
::
ref
(
sum
),
i
);
threads
.
push_back
(
std
::
move
(
t
));
}
...
...
@@ -52,5 +57,5 @@ TEST(ThreadPool, ConcurrentStart) {
t
.
join
();
}
pool
->
Wait
();
EXPECT_EQ
(
sum
,
((
concurrent_cnt
+
1
)
*
concurrent_cnt
)
/
2
);
EXPECT_EQ
(
sum
,
((
n
+
1
)
*
n
)
/
2
);
}
编辑
预览
Markdown
is supported
0%
请重试
或
添加新附件
.
添加附件
取消
You are about to add
0
people
to the discussion. Proceed with caution.
先完成此消息的编辑!
取消
想要评论请
注册
或
登录