提交 633967f9 编写于 作者: P Pierre Bourdon 提交者: Tom Rini

fs: btrfs: fix false negatives in ROOT_ITEM search

ROOT_ITEMs in btrfs are referenced without knowing their actual "offset"
value. To perform these searches using only two items from the key, the
btrfs driver uses a special "btrfs_search_tree_key_type" function.

The algorithm used by that function to transform a 3-tuple search into a
2-tuple search was subtly broken, leading to items not being found if
they were the first in their tree node.

This commit fixes btrfs_search_tree_key_type to properly behave in these
situations.
Signed-off-by: NPierre Bourdon <delroth@gmail.com>
Cc: Marek Behun <marek.behun@nic.cz>
上级 74ee9dc5
......@@ -292,20 +292,52 @@ btrfs_search_tree_key_type(const struct btrfs_root *root, u64 objectid,
{
struct btrfs_key key, *res;
/*
* In some cases (e.g. tree roots), we need to look for a given
* objectid and type without knowing the offset value (3rd element of a
* btrfs tree node key). We can rely on the fact that btrfs_search_tree
* returns the first element with key >= search_key, and then perform
* our own comparison between the returned element and the search key.
*
* It is tempting to use a search key with offset 0 to perform this
* "fuzzy search". This would return the first item with the (objectid,
* type) we're looking for. However, using offset 0 has the wrong
* behavior when the wanted item is the first in a leaf: since our
* search key will be lower than the wanted item, the recursive search
* will explore the wrong branch of the tree.
*
* Instead, use the largest possible offset (-1). The result of this
* search will either be:
* 1. An element with the (objectid, type) we're looking for, if it
* has offset -1 or if it is the last element in its leaf.
* 2. The first element *after* an element with the (objectid, type)
*/
key.objectid = objectid;
key.type = type;
key.offset = 0;
key.offset = -1;
if (btrfs_search_tree(root, &key, path))
return NULL;
res = btrfs_path_leaf_key(path);
if (btrfs_comp_keys_type(&key, res)) {
btrfs_free_path(path);
return NULL;
/*
* Compare with the previous element first -- this is the likely case
* since the result of the search is only what we want if it had offset
* == -1 or if it was last in its leaf.
*/
if (path->slots[0] > 0) {
path->slots[0]--;
res = btrfs_path_leaf_key(path);
if (!btrfs_comp_keys_type(&key, res))
return res;
path->slots[0]++;
}
return res;
res = btrfs_path_leaf_key(path);
if (!btrfs_comp_keys_type(&key, res))
return res;
btrfs_free_path(path);
return NULL;
}
static inline u32 btrfs_path_item_size(struct btrfs_path *p)
......
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