提交 c53a5308 编写于 作者: D Dr. Stephen Henson

Oops, get selection logic right.

上级 f1f7598c
...@@ -3908,9 +3908,10 @@ long ssl3_ctx_ctrl(SSL_CTX *ctx, int cmd, long larg, void *parg) ...@@ -3908,9 +3908,10 @@ long ssl3_ctx_ctrl(SSL_CTX *ctx, int cmd, long larg, void *parg)
break; break;
case SSL_CTRL_GET_EXTRA_CHAIN_CERTS: case SSL_CTRL_GET_EXTRA_CHAIN_CERTS:
*(STACK_OF(X509) **)parg = ctx->extra_certs; if (ctx->extra_certs == NULL && larg == 0)
if (parg == NULL && larg == 0)
*(STACK_OF(X509) **)parg = ctx->cert->key->chain; *(STACK_OF(X509) **)parg = ctx->cert->key->chain;
else
*(STACK_OF(X509) **)parg = ctx->extra_certs;
break; break;
case SSL_CTRL_CLEAR_EXTRA_CHAIN_CERTS: case SSL_CTRL_CLEAR_EXTRA_CHAIN_CERTS:
......
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