提交 6dd9b0fc 编写于 作者: A Andy Polyakov

e_rc4_hmac_md5.c: harmonize zero-length fragment handling with

e_aes_cbc_hmac_sha1.c (mostly for aesthetic reasons).
上级 e36f6b9c
......@@ -75,6 +75,8 @@ typedef struct
size_t payload_length;
} EVP_RC4_HMAC_MD5;
#define NO_PAYLOAD_LENGTH ((size_t)-1)
void rc4_md5_enc (RC4_KEY *key, const void *in0, void *out,
MD5_CTX *ctx,const void *inp,size_t blocks);
......@@ -93,7 +95,7 @@ static int rc4_hmac_md5_init_key(EVP_CIPHER_CTX *ctx,
key->tail = key->head;
key->md = key->head;
key->payload_length = 0;
key->payload_length = NO_PAYLOAD_LENGTH;
return 1;
}
......@@ -122,10 +124,10 @@ static int rc4_hmac_md5_cipher(EVP_CIPHER_CTX *ctx, unsigned char *out,
#endif
size_t plen = key->payload_length;
if (plen && len!=(plen+MD5_DIGEST_LENGTH)) return 0;
if (plen!=NO_PAYLOAD_LENGTH && len!=(plen+MD5_DIGEST_LENGTH)) return 0;
if (ctx->encrypt) {
if (plen==0) plen = len;
if (plen==NO_PAYLOAD_LENGTH) plen = len;
#if defined(STITCHED_CALL)
/* cipher has to "fall behind" */
if (rc4_off>md5_off) md5_off+=MD5_CBLOCK;
......@@ -190,7 +192,7 @@ static int rc4_hmac_md5_cipher(EVP_CIPHER_CTX *ctx, unsigned char *out,
#endif
/* decrypt HMAC at once */
RC4(&key->ks,len-rc4_off,in+rc4_off,out+rc4_off);
if (plen) { /* "TLS" mode of operation */
if (plen!=NO_PAYLOAD_LENGTH) { /* "TLS" mode of operation */
MD5_Update(&key->md,out+md5_off,plen-md5_off);
/* calculate HMAC and verify it */
......@@ -206,7 +208,7 @@ static int rc4_hmac_md5_cipher(EVP_CIPHER_CTX *ctx, unsigned char *out,
}
}
key->payload_length = 0;
key->payload_length = NO_PAYLOAD_LENGTH;
return 1;
}
......
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