提交 3231e42d 编写于 作者: D Dr. Stephen Henson

update pkey method initialisation and copy

上级 cd366cf7
......@@ -293,6 +293,8 @@ EVP_PKEY_ASN1_METHOD* EVP_PKEY_asn1_new(int id, int flags,
if (!ameth)
return NULL;
memset(ameth, 0, sizeof(EVP_PKEY_ASN1_METHOD));
ameth->pkey_id = id;
ameth->pkey_base_id = id;
ameth->pkey_flags = flags | ASN1_PKEY_DYNAMIC;
......@@ -327,6 +329,9 @@ EVP_PKEY_ASN1_METHOD* EVP_PKEY_asn1_new(int id, int flags,
ameth->old_priv_encode = 0;
ameth->old_priv_decode = 0;
ameth->item_verify = 0;
ameth->item_sign = 0;
ameth->pkey_size = 0;
ameth->pkey_bits = 0;
......@@ -378,6 +383,9 @@ void EVP_PKEY_asn1_copy(EVP_PKEY_ASN1_METHOD *dst,
dst->pkey_free = src->pkey_free;
dst->pkey_ctrl = src->pkey_ctrl;
dst->item_sign = src->item_sign;
dst->item_verify = src->item_verify;
}
void EVP_PKEY_asn1_free(EVP_PKEY_ASN1_METHOD *ameth)
......
......@@ -204,6 +204,8 @@ EVP_PKEY_METHOD* EVP_PKEY_meth_new(int id, int flags)
if (!pmeth)
return NULL;
memset(pmeth, 0, sizeof(EVP_PKEY_METHOD));
pmeth->pkey_id = id;
pmeth->flags = flags | EVP_PKEY_FLAG_DYNAMIC;
......
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