提交 0f995b2f 编写于 作者: R Richard Levitte

Small bugfix: even when r == d, we need to adjust r and q.

PR: 366
上级 848f735a
......@@ -202,7 +202,7 @@ n=12 ;(AP) n by value (input)
; r = r - d
; q = q + 1
; }
; while (r > d)
; while (r >= d)
; {
; r = r - d
; q = q + 1
......@@ -253,21 +253,21 @@ d=12 ;(AP) d by value (input)
3$:
tstl r3
bgeq 4$
incl r6 ; since the high bit in r is set, set rprim
incl r6 ; since the high bit in r is set, set r'
4$:
ashl #1,r2,r2
ashl #1,r3,r3
addl r5,r3
ashl #1,r2,r2 ; q = q << 1
ashl #1,r3,r3 ; r = r << 1
addl r5,r3 ; r = r + a'
tstl r6
beql 5$
subl r4,r3
incl r2
beql 5$ ; if r'
subl r4,r3 ; r = r - d
incl r2 ; q = q + 1
5$:
cmpl r3,r4
blequ 42$
subl r4,r3
incl r2
blssu 42$ ; while r >= d
subl r4,r3 ; r = r - d
incl r2 ; q = q + 1
brb 5$
42$:
; movl r3,r1
......
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