提交 633a26c1 编写于 作者: R Rich Felker

fix potential overflow in exponent reading

note that there's no need for a precise cutoff, because exponents this
large will always result in overflow or underflow (it's impossible to
read enough digits to compensate for the exponent magnitude; even at a
few nanoseconds per digit it would take hundreds of years).
上级 c5ff2969
......@@ -44,7 +44,7 @@ static long long scanexp(FILE *f, int pok)
}
for (x=0; c-'0'<10U && x<INT_MAX/10; c = shgetc(f))
x = 10*x + c-'0';
for (y=x; c-'0'<10U && x<LLONG_MAX/10; c = shgetc(f))
for (y=x; c-'0'<10U && x<LLONG_MAX/100; c = shgetc(f))
y = 10*y + c-'0';
for (; c-'0'<10U; c = shgetc(f));
shunget(f);
......
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