提交 23577256 编写于 作者: Y Yong Zhang 提交者: Ingo Molnar

sched: Remove member rt_se from struct rt_rq

It's a duplicate of tg->rt_se[cpu] and the only usage is
sched_rt_rq_dequeue() and sched_rt_rq_enqueue(). After the
first patch to those two function. rt_se can be removed.
Signed-off-by: NYong Zhang <yong.zhang0@gmail.com>
Cc: Rusty Russell <rusty@rustcorp.com.au>
Signed-off-by: NPeter Zijlstra <a.p.zijlstra@chello.nl>
LKML-Reference: <2674af741001282258q38781619u653ca4a7dd267347@mail.gmail.com>
Signed-off-by: NIngo Molnar <mingo@elte.hu>
上级 74b7eb58
......@@ -436,7 +436,6 @@ struct rt_rq {
struct rq *rq;
struct list_head leaf_rt_rq_list;
struct task_group *tg;
struct sched_rt_entity *rt_se;
#endif
};
......@@ -7592,7 +7591,6 @@ static void init_tg_rt_entry(struct task_group *tg, struct rt_rq *rt_rq,
tg->rt_rq[cpu] = rt_rq;
init_rt_rq(rt_rq, rq);
rt_rq->tg = tg;
rt_rq->rt_se = rt_se;
rt_rq->rt_runtime = tg->rt_bandwidth.rt_runtime;
if (add)
list_add(&rt_rq->leaf_rt_rq_list, &rq->leaf_rt_rq_list);
......
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