in _rtl92c_phy_calculate_bit_shift everytime the right shifted bitmask
is AND with 1 and compared against 1. i.e.
       if ((bitmask >> i) & 0x1 == 1)
               break;
which in the if condition is anyway becomes a 1 or 0.
Signed-off-by: NDevendra.Naga <devendra.aaru@gmail.com>
Signed-off-by: NJohn W. Linville <linville@tuxdriver.com>