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由 Wenli Quan 提交于
The largest timeout_netperf_start should be int(l) * 0.5, if netperf threads start all at once, it will still need int(l) * 0.5 time waste. Therefore, the netperf_start_timeout overhead is not needed. Signed-off-by: NWenli Quan <wquan@redhat.com>
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