1. 06 5月, 2014 3 次提交
  2. 01 5月, 2014 1 次提交
  3. 29 4月, 2014 2 次提交
  4. 28 4月, 2014 1 次提交
  5. 27 4月, 2014 2 次提交
  6. 23 4月, 2014 11 次提交
  7. 12 4月, 2014 1 次提交
    • D
      net: Fix use after free by removing length arg from sk_data_ready callbacks. · 676d2369
      David S. Miller 提交于
      Several spots in the kernel perform a sequence like:
      
      	skb_queue_tail(&sk->s_receive_queue, skb);
      	sk->sk_data_ready(sk, skb->len);
      
      But at the moment we place the SKB onto the socket receive queue it
      can be consumed and freed up.  So this skb->len access is potentially
      to freed up memory.
      
      Furthermore, the skb->len can be modified by the consumer so it is
      possible that the value isn't accurate.
      
      And finally, no actual implementation of this callback actually uses
      the length argument.  And since nobody actually cared about it's
      value, lots of call sites pass arbitrary values in such as '0' and
      even '1'.
      
      So just remove the length argument from the callback, that way there
      is no confusion whatsoever and all of these use-after-free cases get
      fixed as a side effect.
      
      Based upon a patch by Eric Dumazet and his suggestion to audit this
      issue tree-wide.
      Signed-off-by: NDavid S. Miller <davem@davemloft.net>
      676d2369
  8. 08 4月, 2014 1 次提交
  9. 04 4月, 2014 1 次提交
  10. 29 3月, 2014 2 次提交
  11. 28 3月, 2014 10 次提交
  12. 25 3月, 2014 1 次提交
    • E
      tipc: fix spinlock recursion bug for failed subscriptions · a5d0e7c0
      Erik Hugne 提交于
      If a topology event subscription fails for any reason, such as out
      of memory, max number reached or because we received an invalid
      request the correct behavior is to terminate the subscribers
      connection to the topology server. This is currently broken and
      produces the following oops:
      
      [27.953662] tipc: Subscription rejected, illegal request
      [27.955329] BUG: spinlock recursion on CPU#1, kworker/u4:0/6
      [27.957066]  lock: 0xffff88003c67f408, .magic: dead4ead, .owner: kworker/u4:0/6, .owner_cpu: 1
      [27.958054] CPU: 1 PID: 6 Comm: kworker/u4:0 Not tainted 3.14.0-rc6+ #5
      [27.960230] Hardware name: Bochs Bochs, BIOS Bochs 01/01/2011
      [27.960874] Workqueue: tipc_rcv tipc_recv_work [tipc]
      [27.961430]  ffff88003c67f408 ffff88003de27c18 ffffffff815c0207 ffff88003de1c050
      [27.962292]  ffff88003de27c38 ffffffff815beec5 ffff88003c67f408 ffffffff817f0a8a
      [27.963152]  ffff88003de27c58 ffffffff815beeeb ffff88003c67f408 ffffffffa0013520
      [27.964023] Call Trace:
      [27.964292]  [<ffffffff815c0207>] dump_stack+0x45/0x56
      [27.964874]  [<ffffffff815beec5>] spin_dump+0x8c/0x91
      [27.965420]  [<ffffffff815beeeb>] spin_bug+0x21/0x26
      [27.965995]  [<ffffffff81083df6>] do_raw_spin_lock+0x116/0x140
      [27.966631]  [<ffffffff815c6215>] _raw_spin_lock_bh+0x15/0x20
      [27.967256]  [<ffffffffa0008540>] subscr_conn_shutdown_event+0x20/0xa0 [tipc]
      [27.968051]  [<ffffffffa000fde4>] tipc_close_conn+0xa4/0xb0 [tipc]
      [27.968722]  [<ffffffffa00101ba>] tipc_conn_terminate+0x1a/0x30 [tipc]
      [27.969436]  [<ffffffffa00089a2>] subscr_conn_msg_event+0x1f2/0x2f0 [tipc]
      [27.970209]  [<ffffffffa0010000>] tipc_receive_from_sock+0x90/0xf0 [tipc]
      [27.970972]  [<ffffffffa000fa79>] tipc_recv_work+0x29/0x50 [tipc]
      [27.971633]  [<ffffffff8105dbf5>] process_one_work+0x165/0x3e0
      [27.972267]  [<ffffffff8105e869>] worker_thread+0x119/0x3a0
      [27.972896]  [<ffffffff8105e750>] ? manage_workers.isra.25+0x2a0/0x2a0
      [27.973622]  [<ffffffff810648af>] kthread+0xdf/0x100
      [27.974168]  [<ffffffff810647d0>] ? kthread_create_on_node+0x1a0/0x1a0
      [27.974893]  [<ffffffff815ce13c>] ret_from_fork+0x7c/0xb0
      [27.975466]  [<ffffffff810647d0>] ? kthread_create_on_node+0x1a0/0x1a0
      
      The recursion occurs when subscr_terminate tries to grab the
      subscriber lock, which is already taken by subscr_conn_msg_event.
      We fix this by checking if the request to establish a new
      subscription was successful, and if not we initiate termination of
      the subscriber after we have released the subscriber lock.
      Signed-off-by: NErik Hugne <erik.hugne@ericsson.com>
      Reviewed-by: NJon Maloy <jon.maloy@ericsson.com>
      Signed-off-by: NDavid S. Miller <davem@davemloft.net>
      a5d0e7c0
  13. 13 3月, 2014 4 次提交