提交 e13ed9b2 编写于 作者: H Heiko Carstens 提交者: Martin Schwidefsky

[S390] bitops: remove likely annotations

likely/unlikely profiling revealed that none of the branches in bitops
is taken likely or unlikely. So remove the annotations.
In addition the generated code is shorter.
Signed-off-by: NHeiko Carstens <heiko.carstens@de.ibm.com>
Signed-off-by: NMartin Schwidefsky <schwidefsky@de.ibm.com>
上级 ced2c8bc
......@@ -525,16 +525,16 @@ static inline unsigned long __ffs_word_loop(const unsigned long *addr,
static inline unsigned long __ffz_word(unsigned long nr, unsigned long word)
{
#ifdef __s390x__
if (likely((word & 0xffffffff) == 0xffffffff)) {
if ((word & 0xffffffff) == 0xffffffff) {
word >>= 32;
nr += 32;
}
#endif
if (likely((word & 0xffff) == 0xffff)) {
if ((word & 0xffff) == 0xffff) {
word >>= 16;
nr += 16;
}
if (likely((word & 0xff) == 0xff)) {
if ((word & 0xff) == 0xff) {
word >>= 8;
nr += 8;
}
......@@ -549,16 +549,16 @@ static inline unsigned long __ffz_word(unsigned long nr, unsigned long word)
static inline unsigned long __ffs_word(unsigned long nr, unsigned long word)
{
#ifdef __s390x__
if (likely((word & 0xffffffff) == 0)) {
if ((word & 0xffffffff) == 0) {
word >>= 32;
nr += 32;
}
#endif
if (likely((word & 0xffff) == 0)) {
if ((word & 0xffff) == 0) {
word >>= 16;
nr += 16;
}
if (likely((word & 0xff) == 0)) {
if ((word & 0xff) == 0) {
word >>= 8;
nr += 8;
}
......
Markdown is supported
0% .
You are about to add 0 people to the discussion. Proceed with caution.
先完成此消息的编辑!
想要评论请 注册