time: don't inline EXPORT_SYMBOL functions

How is the compiler even handling exported functions that are marked
inline? Anyway, these shouldn't be inline because of that, so remove
that marking.

Based on a larger patch by Mark Charlebois to get LLVM to build the
kernel.

Cc: Thomas Gleixner <tglx@linutronix.de>
Cc: Mark Charlebois <mcharleb@qualcomm.com>
Cc: Paul Gortmaker <paul.gortmaker@windriver.com>
Cc: hank <pyu@redhat.com>
Cc: John Stultz <john.stultz@linaro.org>
Signed-off-by: NGreg Kroah-Hartman <gregkh@linuxfoundation.org>
Signed-off-by: NAndrew Morton <akpm@linux-foundation.org>
Signed-off-by: NLinus Torvalds <torvalds@linux-foundation.org>

kernel/time.c

@@ -240,7 +240,7 @@ EXPORT_SYMBOL(current_fs_time);
  * Avoid unnecessary multiplications/divisions in the
  * two most common HZ cases:
  */
-inline unsigned int jiffies_to_msecs(const unsigned long j)
+unsigned int jiffies_to_msecs(const unsigned long j)
 {
 #if HZ <= MSEC_PER_SEC && !(MSEC_PER_SEC % HZ)
 	return (MSEC_PER_SEC / HZ) * j;
@@ -256,7 +256,7 @@ inline unsigned int jiffies_to_msecs(const unsigned long j)
 }
 EXPORT_SYMBOL(jiffies_to_msecs);
 
-inline unsigned int jiffies_to_usecs(const unsigned long j)
+unsigned int jiffies_to_usecs(const unsigned long j)
 {
 #if HZ <= USEC_PER_SEC && !(USEC_PER_SEC % HZ)
 	return (USEC_PER_SEC / HZ) * j;