提交 98eb2f8b 编写于 作者: P Paolo Bonzini

KVM: vmx: speed up emulation of invalid guest state

About 25% of the time spent in emulation of invalid guest state
is wasted in checking whether emulation is required for the next
instruction.  However, this almost never changes except when a
segment register (or TR or LDTR) changes, or when there is a mode
transition (i.e. CR0 changes).

In fact, vmx_set_segment and vmx_set_cr0 already modify
vmx->emulation_required (except that the former for some reason
uses |= instead of just an assignment).  So there is no need to
call guest_state_valid in the emulation loop.

Emulation performance test results indicate 1650-2600 cycles
for common instructions, versus 2300-3200 before this patch on
a Sandy Bridge Xeon.
Signed-off-by: NPaolo Bonzini <pbonzini@redhat.com>
上级 22d48b2d
......@@ -3672,7 +3672,7 @@ static void vmx_set_segment(struct kvm_vcpu *vcpu,
vmcs_write32(sf->ar_bytes, vmx_segment_access_rights(var));
out:
vmx->emulation_required |= emulation_required(vcpu);
vmx->emulation_required = emulation_required(vcpu);
}
static void vmx_get_cs_db_l_bits(struct kvm_vcpu *vcpu, int *db, int *l)
......@@ -5640,7 +5640,7 @@ static int handle_invalid_guest_state(struct kvm_vcpu *vcpu)
cpu_exec_ctrl = vmcs_read32(CPU_BASED_VM_EXEC_CONTROL);
intr_window_requested = cpu_exec_ctrl & CPU_BASED_VIRTUAL_INTR_PENDING;
while (!guest_state_valid(vcpu) && count-- != 0) {
while (vmx->emulation_required && count-- != 0) {
if (intr_window_requested && vmx_interrupt_allowed(vcpu))
return handle_interrupt_window(&vmx->vcpu);
......@@ -5674,7 +5674,6 @@ static int handle_invalid_guest_state(struct kvm_vcpu *vcpu)
schedule();
}
vmx->emulation_required = emulation_required(vcpu);
out:
return ret;
}
......
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