提交 86ba9ed9 编写于 作者: Y Yaowei Bai 提交者: Richard Weinberger

fs/ubifs: remove unnecessary new_valid_dev check

As currently new_valid_dev always returns 1, so new_valid_dev check is not
needed, remove it.
Signed-off-by: NYaowei Bai <bywxiaobai@163.com>
Reviewed-by: NRichard Weinberger <richard@nod.at>
Signed-off-by: NArtem Bityutskiy <artem.bityutskiy@linux.intel.com>
Signed-off-by: NRichard Weinberger <richard@nod.at>
上级 1cb8f977
无相关合并请求
......@@ -787,9 +787,6 @@ static int ubifs_mknod(struct inode *dir, struct dentry *dentry,
dbg_gen("dent '%pd' in dir ino %lu", dentry, dir->i_ino);
if (!new_valid_dev(rdev))
return -EINVAL;
if (S_ISBLK(mode) || S_ISCHR(mode)) {
dev = kmalloc(sizeof(union ubifs_dev_desc), GFP_NOFS);
if (!dev)
......
......@@ -155,13 +155,8 @@ static inline int ubifs_wbuf_sync(struct ubifs_wbuf *wbuf)
*/
static inline int ubifs_encode_dev(union ubifs_dev_desc *dev, dev_t rdev)
{
if (new_valid_dev(rdev)) {
dev->new = cpu_to_le32(new_encode_dev(rdev));
return sizeof(dev->new);
} else {
dev->huge = cpu_to_le64(huge_encode_dev(rdev));
return sizeof(dev->huge);
}
dev->new = cpu_to_le32(new_encode_dev(rdev));
return sizeof(dev->new);
}
/**
......
Markdown is supported
0% .
You are about to add 0 people to the discussion. Proceed with caution.
先完成此消息的编辑!
想要评论请 注册
反馈
建议
客服 返回
顶部