提交 69efcc6d 编写于 作者: Y Yinghai Lu 提交者: Tejun Heo

x86-64, NUMA: Do not scan two times for setup_node_bootmem()

By the time setup_node_bootmem() is called, all the memblocks are
already registered.  As node_data is allocated from these memblocks,
calling it more than once doesn't make any difference.  Drop the loop.

tj: Dropped comment referencing to the old behavior as suggested by
    David and rephrased the description.
Signed-off-by: NYinghai Lu <yinghai@kernel.org>
Acked-by: NDavid Rientjes <rientjes@google.com>
Signed-off-by: NTejun Heo <tj@kernel.org>
上级 6d496f9f
......@@ -480,7 +480,7 @@ static bool __init numa_meminfo_cover_memory(const struct numa_meminfo *mi)
static int __init numa_register_memblks(struct numa_meminfo *mi)
{
int i, j, nid;
int i, nid;
/* Account for nodes with cpus and no memory */
node_possible_map = numa_nodes_parsed;
......@@ -506,28 +506,20 @@ static int __init numa_register_memblks(struct numa_meminfo *mi)
init_memory_mapping_high();
/*
* Finally register nodes. Do it twice in case setup_node_bootmem
* missed one due to missing bootmem.
*/
for (i = 0; i < 2; i++) {
for_each_node_mask(nid, node_possible_map) {
u64 start = (u64)max_pfn << PAGE_SHIFT;
u64 end = 0;
/* Finally register nodes. */
for_each_node_mask(nid, node_possible_map) {
u64 start = (u64)max_pfn << PAGE_SHIFT;
u64 end = 0;
if (node_online(nid))
for (i = 0; i < mi->nr_blks; i++) {
if (nid != mi->blk[i].nid)
continue;
for (j = 0; j < mi->nr_blks; j++) {
if (nid != mi->blk[j].nid)
continue;
start = min(mi->blk[j].start, start);
end = max(mi->blk[j].end, end);
}
if (start < end)
setup_node_bootmem(nid, start, end);
start = min(mi->blk[i].start, start);
end = max(mi->blk[i].end, end);
}
if (start < end)
setup_node_bootmem(nid, start, end);
}
return 0;
......
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