提交 5967fe22 编写于 作者: M Mark Rustad 提交者: Jeff Kirsher

ixgbe: Correct error path in semaphore handling

The timeout path is supposed to release the semaphore, so do that.
Signed-off-by: NMark Rustad <mark.d.rustad@intel.com>
Tested-by: NPhil Schmitt <phillip.j.schmitt@intel.com>
Signed-off-by: NJeff Kirsher <jeffrey.t.kirsher@intel.com>
上级 449e21a9
......@@ -711,6 +711,11 @@ static s32 ixgbe_get_swfw_sync_semaphore(struct ixgbe_hw *hw)
usleep_range(50, 100);
}
/* Release semaphores and return error if SW NVM semaphore
* was not granted because we do not have access to the EEPROM
*/
hw_dbg(hw, "REGSMP Software NVM semaphore not granted\n");
ixgbe_release_swfw_sync_semaphore(hw);
return IXGBE_ERR_EEPROM;
}
......
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