提交 49f2186d 编写于 作者: R Ron Mercer 提交者: David S. Miller

qlge: Optimize rx buffer refill process.

RX Buffers are refilled in chunks of 16 at a time before notifying the
hardware with a register write.  This can cause several writes to take
place in a given napi poll call.  This change causes the write to take place
only once at the end of the call.
Signed-off-by: NRon Mercer <ron.mercer@qlogic.com>
Signed-off-by: NDavid S. Miller <davem@davemloft.net>
上级 8587ea35
......@@ -863,7 +863,8 @@ static void ql_write_cq_idx(struct rx_ring *rx_ring)
/* Process (refill) a large buffer queue. */
static void ql_update_lbq(struct ql_adapter *qdev, struct rx_ring *rx_ring)
{
int clean_idx = rx_ring->lbq_clean_idx;
u32 clean_idx = rx_ring->lbq_clean_idx;
u32 start_idx = clean_idx;
struct bq_desc *lbq_desc;
u64 map;
int i;
......@@ -910,19 +911,23 @@ static void ql_update_lbq(struct ql_adapter *qdev, struct rx_ring *rx_ring)
rx_ring->lbq_prod_idx += 16;
if (rx_ring->lbq_prod_idx == rx_ring->lbq_len)
rx_ring->lbq_prod_idx = 0;
rx_ring->lbq_free_cnt -= 16;
}
if (start_idx != clean_idx) {
QPRINTK(qdev, RX_STATUS, DEBUG,
"lbq: updating prod idx = %d.\n",
rx_ring->lbq_prod_idx);
ql_write_db_reg(rx_ring->lbq_prod_idx,
rx_ring->lbq_prod_idx_db_reg);
rx_ring->lbq_free_cnt -= 16;
}
}
/* Process (refill) a small buffer queue. */
static void ql_update_sbq(struct ql_adapter *qdev, struct rx_ring *rx_ring)
{
int clean_idx = rx_ring->sbq_clean_idx;
u32 clean_idx = rx_ring->sbq_clean_idx;
u32 start_idx = clean_idx;
struct bq_desc *sbq_desc;
u64 map;
int i;
......@@ -972,13 +977,15 @@ static void ql_update_sbq(struct ql_adapter *qdev, struct rx_ring *rx_ring)
rx_ring->sbq_prod_idx += 16;
if (rx_ring->sbq_prod_idx == rx_ring->sbq_len)
rx_ring->sbq_prod_idx = 0;
rx_ring->sbq_free_cnt -= 16;
}
if (start_idx != clean_idx) {
QPRINTK(qdev, RX_STATUS, DEBUG,
"sbq: updating prod idx = %d.\n",
rx_ring->sbq_prod_idx);
ql_write_db_reg(rx_ring->sbq_prod_idx,
rx_ring->sbq_prod_idx_db_reg);
rx_ring->sbq_free_cnt -= 16;
}
}
......
Markdown is supported
0% .
You are about to add 0 people to the discussion. Proceed with caution.
先完成此消息的编辑!
想要评论请 注册